Next term of the following sequence is : A^(3/2) B_(2), C^(9/2) F_(18), E^(15/2) J_(50), G^(21/2) N_(98), ?
- (1)H^(29/2) S_(172)
- (2)H^(27/2) R_(182)
- (3)I^(27/2) R_(162)
- (4)I^(29/2) R_(172)
Answer
Why
Correct — option (3), I^(27/2) R_(162).
The booklet prints each first letter with a superscript and each second letter with a subscript; here they appear as ^( ) and _( ). Each term has four parts, and each part gets its own rule.
Step 1 — first letters.
A, C, E, G = positions 1, 3, 5, 7, rising by 2
Next: position 9 = I
Step 2 — second letters.
B, F, J, N = positions 2, 6, 10, 14, rising by 4
Next: position 18 = R
Step 3 — superscripts.
3/2, 9/2, 15/2, 21/2, each rising by 6/2 = 3
Next: 21/2 + 6/2 = 27/2
Step 4 — subscripts.
2, 18, 50, 98: differences 16, 32, 48, rising by 16
Next difference 64: 98 + 64 = 162
Next term: I^(27/2) R_(162)
Check with the first letter's position n = 1, 3, 5, 7, 9: second letter = 2n, superscript = 3n/2, subscript = 2n². For n = 9: R (18), 27/2 and 2 × 81 = 162.
The idea to remember: in a mixed letter–number series, split each term into its parts and find a rule for each part.
Why the others are wrong
- (1)H^(29/2) S_(172) — Option (1) misses all four parts. H is position 8, but the first letters step by 2 from G (7) to I (9). S is position 19, off the step of 4 that takes N (14) to R (18).
The superscripts rise by 3, so 21/2 goes to 27/2, not 29/2. The subscript differences 16, 32, 48 continue with 64, giving 162, not 172.
- (2)H^(27/2) R_(182) — Option (2) has the right second letter, R, and the right superscript, 27/2, but breaks the other two parts.
The first letters rise by 2 from G (7) to I (9), not H (8). The subscripts 2, 18, 50, 98 are 2 × 1², 2 × 3², 2 × 5², 2 × 7², so the next is 2 × 9² = 162, not 182.
- (4)I^(29/2) R_(172) — Option (4) has both letters right, I and R, but both numbers are off.
The superscripts rise by exactly 3 each time: 3/2, 9/2, 15/2, 21/2, 27/2; reaching 29/2 would need a step of 4. The subscript differences 16, 32, 48, 64 give 98 + 64 = 162, not 172.
Concept
A letter series works on alphabet positions, A = 1 to Z = 26. Steps can go forward or backward, stay constant or grow.
A number series can rise by a fixed difference, by differences that themselves follow a pattern, or by a formula such as n² or n³.
When each term has several parts, every part can follow its own rule. The parts can also share one counter: here all four depend on the first letter's position, 1, 3, 5, 7, 9.
RPSC's 2023 syllabus lists "Number /Letter sequences" under Mental Ability in Reasoning & Mental Ability.
Anchors for letter positions: E = 5, J = 10, O = 15, T = 20, Y = 25. A letter's position counted from Z is 27 minus its position counted from A.
The difference method used on the subscripts is finite-difference reasoning. When the second differences of a sequence are constant, the terms follow a quadratic rule; 2, 18, 50, 98 have second difference 16 and follow 2n² for odd n.
Key facts
- Alphabet positions: A = 1, E = 5, J = 10, O = 15, T = 20, Y = 25, Z = 26.
- First letters A, C, E, G, I rise by 2; second letters B, F, J, N, R rise by 4.
- Superscripts 3/2, 9/2, 15/2, 21/2, 27/2 rise by 3 each time.
- Subscripts 2, 18, 50, 98, 162 equal 2 × 1², 2 × 3², 2 × 5², 2 × 7², 2 × 9².
- Constant second differences in a number sequence point to a quadratic rule; here the second difference is 16.
Second letter at position 2n, superscript 3n/2, subscript 2n².
Study next
Common traps
- Stepping the first letter by 1 to H. The first letters skip a letter each time, A, C, E, G, so the next is I.
- Stepping the superscript by 4. The numerators 3, 9, 15, 21 rise by 6, so each superscript rises by 3 and the next is 27/2; a step of 4 gives the 29/2 in options (1) and (4).
- Treating the subscript difference as constant. The differences 16, 32, 48 themselves rise by 16, so the next is 64; repeating 48 would give 146.
A question can combine letters and numbers in one term, as this one does, or give a pure letter series or a pure number series.
A question can hide the rule in positions, squares or cubes, or in differences that themselves grow.
Related PYQs
Next term in the following sequence is : 2, 12, 36, 80, 150, ?
- (1) 210
- (2) 252
- (3) 258
- (4) 270
Answer(2)
Same search for a power-based rule in a number sequence. There 2, 12, 36, 80, 150 are n³ + n² for n = 1 to 5 (RPSC's key: option (2), 252); here the subscripts 2, 18, 50, 98 are 2n² for n = 1, 3, 5, 7.
Practice
- practice — not a real PYQ
Next term of the following sequence is : 1A1, 3C9, 5E25, 7G49, ?
- (a)9I81
- (b)9H81
- (c)8I64
- (d)9I72
Answer(1) — The first number rises by 2 (1, 3, 5, 7, 9); the letter sits at that position (A = 1, C = 3, E = 5, G = 7, I = 9); the last number is the square of the first (81).Option (2) puts H (8) at position 9, option (3) steps the first number by 1, and option (4) gives 72, which is not 9².
- practice — not a real PYQ
Next term of the following sequence is : AZ, CX, EV, GT, ?
- (a)HS
- (b)IR
- (c)IS
- (d)JQ
Answer(2) — The first letters move forward by 2 (A, C, E, G, I) and the second letters move back by 2 (Z, X, V, T, R). Option (1) moves each letter by 1, option (3) moves the second letter back by only 1, and option (4) moves both letters by 3.