Q travels towards East. M travels towards North. S and T travel in opposite directions. T travels towards right of Q. Which of the following is definitely true?
- (a)M and S travel in the opposite directions
- (b)S travels towards West
- (c)T travels towards North
- (d)M and S travel in the same direction
Answer
Why
Correct: D, M and S travel in the same direction. The chain has only two links and it runs in one direction, so do it in order and do not draw more than a cross on the page.
Link 1: fix T. The stem says T travels towards the right of Q, and Q is travelling East. In a direction-sense question 'the right of' a moving person means that person's own right hand, not the right-hand side of the page, so you turn ninety degrees clockwise from the direction Q faces. Clockwise from East is South. T therefore travels South.
Link 2: fix S. S and T travel in opposite directions, and the opposite of South is North. S therefore travels North.
Now compare. M is given as travelling North and S has just been shown to travel North, so M and S travel in the same direction, which is option (d). Test the other three against the same two deductions and each fails on a fact you have already established: (a) claims M and S are opposite when they are identical; (b) puts S in the West when S is in the North; (c) puts T in the North when T is in the South, and in fact North is the one direction T certainly does not take, since T and S are opposites and S holds the North.
Notice how little of the stem is load-bearing. Q's direction is used once, only to define T's, and is then finished with; M's direction is never derived at all, it is simply given so that there is something to compare S against. No distances are stated anywhere, so nothing here needs coordinates or a Pythagoras step: this is a pure bearing question, and the answer is fully determined, which is what the words 'definitely true' in the stem are checking. Both independent derivations reached D with full confidence, and the reasoning above is closed: there is no reading of the stem on which S and M part company, once 'right of Q' is taken in its standard sense.
Why the others are wrong
- (a)M and S travel in the opposite directions: The exact inverse of the truth, and it is the option you land on if you drop a negation somewhere in the chain: most often by making S the opposite of M rather than the opposite of T. The stem never relates S to M; it relates S to T, and M's direction is supplied separately. Once T is South, S is North, and North is also where M is going, so 'opposite' is precisely wrong.
- (b)S travels towards West: This is the answer to the question as it would read if 'the right of Q' meant the right-hand side of a map. With North at the top of the page, the right-hand side is the East, so that reading makes T travel East, S travel West and option (b) true. It is a manufactured trap, and a good one, because the misreading is silent: nothing later in the question contradicts it. The convention that closes it is that a direction described relative to a person who is moving is taken from that person's own facing; a question that meant the compass East would have said East.
- (c)T travels towards North: T travels South, not North, so this reverses the very first deduction. It is produced either by turning anticlockwise instead of clockwise: treating Q's right as North rather than South, or by correctly working out that somebody goes North and then attaching that to T instead of to S. Keeping the two apart is easy if you write the chain down as Q → T → S rather than trying to hold it in your head, because T and S must always end up on opposite arms of the cross.
Concept
Every direction-sense question rests on the same compass convention: North at the top, South at the bottom, East to the right and West to the left, with North-East, South-East, South-West and North-West on the diagonals. Two operations act on that cross. A right turn is ninety degrees clockwise and a left turn is ninety degrees anticlockwise, both measured from the direction the person is currently facing, which gives the cycle North → East → South → West → North for successive right turns and the same cycle read backwards for left turns. 'Opposite' is a half turn, so the pairs are North with South, East with West, North-East with South-West and North-West with South-East. The one idea that separates a careless solver from a careful one is that these turns are relative to the traveller, not to the sheet of paper: when a question says T goes to the right of Q, it is asking you to stand where Q stands and face where Q faces. Only when a question names a compass point: 'to the east of': is the frame absolute. Where a problem also gives distances, the same cross becomes a coordinate grid and the shortest distance from start to finish is found with Pythagoras; where it gives none, as here, the whole problem is a chain of turns and the answer is a bearing.
Solve it by writing a chain, not by holding four travellers in mind at once. Ask which statement can be resolved with no prior work: 'T travels towards right of Q' can, because Q's direction is given outright. That yields T = South. Then ask which statement now becomes resolvable: 'S and T travel in opposite directions' does, and yields S = North. At that point every traveller has a direction and the options can be read off. The discriminating fact for the whole item is the single conversion right-of-East = South; get that one step right and all four options fall into place, get it wrong in the clockwise sense and you produce option (c), get it wrong in the frame-of-reference sense and you produce option (b). It is also worth registering what 'definitely true' is for. In many items of this family some travellers are left partly free: 'S travels either North or East', and then an option can be possibly true without being definitely true. Here nothing is free: two given directions plus two relations pin all four travellers, so 'definitely' costs you nothing extra. But the habit of asking whether a conclusion is forced or merely available is the habit that saves marks on the harder version of this question.
Key facts
- A right turn is 90 degrees clockwise from the direction faced: facing North the right is East, facing East the right is South, facing South the right is West, facing West the right is North
- A left turn is 90 degrees anticlockwise: facing North the left is West, facing East the left is North, facing South the left is East, facing West the left is South
- Opposite directions are half turns: North with South, East with West, North-East with South-West, North-West with South-East
- The chain here is exactly two steps: Q = East fixes T = South (right of East), and T = South fixes S = North (opposite of South); M = North is given, so M and S coincide
- Directions given relative to a moving person are taken from that person's own facing; only a named compass point such as 'to the east of' is absolute: reading 'right of Q' as the right-hand side of the map is what generates option (b)
- The question states no distances at all, so no coordinate or Pythagoras step is needed; the answer is a bearing, not a displacement
Right of East is South, not East. Reading 'right of Q' as the right-hand side of the page gives T = East and S = West, which is exactly the false trail that makes option (b) look correct.
Study next
Common traps
- Taking 'the right of Q' as the right-hand side of the map, which turns South into East and makes the wrong option look right
- Turning anticlockwise for a right turn, which reverses South and North throughout the chain
- Relating S to M instead of to T: the stem links S only to T, and M is given independently
BPSC keeps a block of reasoning inside the General Studies paper and returns to direction sense almost every year, usually in one of two shapes: a single traveller making a sequence of turns, as in the 71st CCE paper's item on Ram going North and then turning right, right and left; or, as here, several named travellers whose directions are defined against one another and a 'which is definitely true' stem. UPSC set the same material in General Studies Paper I through the 1990s and up to 2000, generally with distances attached so that the answer was a length rather than a bearing; since the CSAT was introduced in 2011 this material has sat in the qualifying Paper II.
Related PYQs
A person starts from a point A and travels 3 km eastwards to B and then turns left and travels thrice that distance to reach C. He again turns left and travels five times the distance he covered between A and B and reaches his destination D. The shortest distance between the starting point and destination is
- (a) 18 km
- (b) 16 km
- (c) 15 km
- (d) 12 km
Answer(c) 15 km
The same turn convention, tested with distances attached. Each 'turns left' there is measured from the direction the walker is already travelling, exactly as 'right of Q' is here (East then left is North, North then left is West) and once the three legs are plotted the answer is a Pythagoras step. Learn the turn rule once and it serves both the bearing version and the distance version.
Ram goes North, turns right, then goes right again and then goes to left. In which direction Ram is now?
- (a) EAST
- (b) SOUTH
- (c) NORTH
- (d) WEST
Answer(a) EAST
BPSC's other standard shape for the same skill, asked two years later: one traveller, a run of turns, and the same rule that a turn is measured from the direction currently faced. North, right to East, right again to South, then left back to East. Between the two cards you have both formats the Commission uses.
Practice
- practice, not a real PYQ
A person is walking towards the West. He turns to his right and then turns to his right again. In which direction is he walking now?
- (a)North
- (b)East
- (c)South
- (d)West
Answer(b) East: a right turn from West faces him North, and a second right turn faces him East; two right turns always reverse the original direction. - practice, not a real PYQ
X travels towards South. Y travels towards the left of X. Z travels in the direction opposite to Y. Which of the following is true?
- (a)Y travels towards West
- (b)Z travels towards West
- (c)Z travels towards North
- (d)Y travels towards North
Answer(b) Z travels towards West: the left of South is East, so Y travels East, and the direction opposite to East is West.