If an object is placed at the focus of a convex lens, its image is
- (a)at the focus on the same side.
- (b)at the focus on the opposite side.
- (c)coincident with the lens.
- (d)at infinity.
Correct — D, at infinity. Put a point source exactly at the focus of a converging lens and the rays that pass through emerge parallel to one another, so they never meet at any finite distance — the image is formed at infinity. The lens formula says the same thing in one line. With the object distance equal to the focal length, 1/v equals 1/f plus 1/(minus f), which is zero, so v is infinite. This is simply the reverse of the everyday case in which parallel rays from a distant object are brought to a point at the focus, and it is the arrangement used in a collimator and in the eyepiece of a telescope adjusted for a relaxed eye.
- (a)at the focus on the same side. — A converging lens sends light onward, not back; for a real object it can only form a real image on the far side, or a virtual one on the near side when the object is nearer than the focus. Nothing is formed at the focus on the object's own side.
- (b)at the focus on the opposite side. — The exact reverse of this situation. An object at infinity gives an image at the focus; an object at the focus gives an image at infinity. Swapping the two is the commonest error on this question.
- (c)coincident with the lens. — An image at the lens would mean v equals zero, which the lens formula produces only when the object itself is at the lens. It is not what an object at the focal point does.
For a thin lens the formula 1/v minus 1/u equals 1/f ties the object distance, the image distance and the focal length together, with distances measured from the optical centre and signs taken along the direction of incident light. Feeding in the standard object positions gives the whole table a candidate needs: beyond twice the focal length gives a real, inverted, diminished image between the focus and twice the focus; at twice the focal length gives a real, inverted, same-size image at twice the focus on the other side; between the focus and twice the focus gives a real, inverted, enlarged image beyond twice the focus; at the focus gives an image at infinity; and inside the focus gives a virtual, erect, enlarged image on the same side.
You do not need the algebra if you remember that a lens is reversible. Light from a distant object arrives as a parallel beam and is brought to the focus; run the light the other way and a source at the focus must send out a parallel beam. Parallel rays meet only at infinity, which settles the answer. The bank's entry for this question carries an image flag, but the stem as printed is complete and self-contained and needs no figure to be answered.
- The thin-lens formula is 1/v minus 1/u equals 1/f, with distances measured from the optical centre.
- An object at the focus of a convex lens gives an image at infinity; an object at infinity gives an image at the focus.
- Rays leaving a point at the focus emerge from the lens parallel to one another.
- An object between the focus and twice the focal length gives a real, inverted and enlarged image beyond twice the focal length.
- An object placed at twice the focal length gives a real, inverted, same-size image at twice the focal length on the other side.
The algebra and the reversibility argument reach the same place, which is worth checking one against the other.
- Swapping the two reciprocal cases — object at infinity against object at the focus.
- Applying the mirror formula's sign rules to a lens.
- Assuming a convex lens always makes a real image; inside the focus it does not.
As a where-is-the-image item like this one, or as a short numerical fixing the object distance from the focal length and the nature of the image wanted.
CDS_GK_2021_II_Q12021Where should an object be placed in front of a convex lens to get a real and enlarged image of the object ?
- (a) At twice the focal length
- (b) At infinity
- (c) Between the principal focus and twice the focal length
- (d) Beyond twice the focal length
Answer(c) Between the principal focus and twice the focal length
The neighbouring row of the same table. That item asks where to stand to get a real enlarged image; this one asks what happens at the boundary of that zone, where the image runs off to infinity.
CDS_GK_2022_I_Q232022A convex lens has a focal length of 15 cm. At what distance should an object be placed in front of the lens to get a real image of the same size of the object ?
- (a) 15 cm
- (b) 10 cm
- (c) 30 cm
- (d) 40 cm
Answer(c) 30 cm
The same table with numbers in it, from the first session of the same year. A same-size real image needs the object at twice the focal length, which is 30 cm — one step further out than the focal point that sends the image to infinity here.
- practice — not a real PYQ
An object placed at infinity in front of a convex lens forms its image at which one of the following positions?
- (a)At the optical centre
- (b)At the focus on the far side
- (c)At twice the focal length
- (d)At infinity on the far side
Answer(b) At the focus on the far side — the reverse of the case in this question, since a lens works equally well in either direction.
- practice — not a real PYQ
For a convex lens, an object placed between the focus and twice the focal length gives an image that is
- (a)virtual, erect and diminished
- (b)real, inverted and of the same size
- (c)real, inverted and enlarged
- (d)virtual, erect and of the same size
Answer(c) real, inverted and enlarged — and it is formed beyond twice the focal length on the far side.