If 8 # 2 = 64, 7 # 3 = 343, then 6 # 2 = ?
- (a)216
- (b)144
- (c)100
- (d)36
Answer
Why
Correct — D.
Rule: a # b = a raised to the power b (aᵇ).
8 # 2 = 8² = 64 ✓
7 # 3 = 7³ = 343 ✓
6 # 2 = 6² = 36 → option (d).
The second example is what fixes the rule: squaring alone would give 7² = 49, not 343.
Why the others are wrong
- (a)216 — 216 is 6³. It borrows the power 3 from 7 # 3, but in 6 # 2 the second number is 2, so the power is 2.
- (b)144 — 144 is (6 × 2)² = 12². Test that rule on 8 # 2: (8 × 2)² = 256, not 64, so it fails the first example.
- (c)100 — 100 is 10², and no power of 6 equals it: 6² = 36 and 6³ = 216. It does not come from 6 # 2 under aᵇ.
Concept
In a symbol-operation question, # has no meaning of its own. The rule is read from the worked examples, and it must fit every example, not just one.
8 # 2 = 64 alone fits several rules, such as a² or a × b × 4. 7 # 3 = 343 settles it: 7² = 49 and 7 × 3 × 4 = 84, but 7³ = 343, so the second number is the power.
Squaring the first number also gives 36 here, because the power in 6 # 2 happens to be 2. That rule fails 7 # 3, so it is not the rule, and on 6 # 3 it would give 36 where aᵇ gives 216.
Key facts
- a # b = aᵇ fits both examples: 8² = 64 and 7³ = 343.
- 6² = 36 and 6³ = 216.
- A rule must be tested on every example given, not just the first.
Study next
Common traps
- Carrying the power 3 from 7 # 3 into 6 # 2 and choosing 216
- Stopping after the first example: squaring fits 8 # 2 = 64 but fails 7 # 3 = 343
17 Sep 2025, 16:00, Reasoning Q.21 prints the same 8 # 2 with a different result, 65, where the rule is a² + b² − 3 and 6 # 5 is keyed 58.
15 Sep 2025, 09:00, Reasoning Q.16 gives 4 # 2 = 10 and 6 # 3 = 21, and keys 8 # 4 as 36.
Related PYQs
No directly related past PYQ was found.