In a code language, TABLE is written as UDCMF. How will CHAIR be written?
- (a)DKBJS
- (b)EJCKS
- (c)DJCKR
- (d)DJBKR
Answer
Why
Correct — A.
Rule: shift by position: +1, +3, +1, +1, +1.
TABLE → UDCMF: T + 1 = U, A + 3 = D, B + 1 = C, L + 1 = M, E + 1 = F.
CHAIR: C + 1 = D, H + 3 = K, A + 1 = B, I + 1 = J, R + 1 = S
→ DKBJS, option (a).
Why the others are wrong
- (b)EJCKS — EJCKS moves C to E, a shift of +2. The first letter of TABLE moves only +1 (T → U), so CHAIR must start with D.
- (c)DJCKR — DJCKR leaves R unchanged at the end, but E → F in TABLE shows the last letter moves +1. It also moves H only +2, to J.
- (d)DJBKR — DJBKR moves H to J, a shift of +2, but the second letter moves +3 (A → D in TABLE). H + 3 is K, so the second letter must be K.
Concept
A letter-shift code moves each letter a set number of places along the alphabet. Here the shift depends on the letter's position in the word, not on the letter itself.
That is why A becomes D in TABLE, where it is 2nd, but B in CHAIR, where it is 3rd. Read the shift for each place off the example, then apply the same five shifts to the new word.
The +3 in second place breaks an otherwise steady +1. The sheet prints UDCMF, and the keyed DKBJS moves its second letter three places too, so the key follows the example exactly.
Key facts
- Shifts read off TABLE → UDCMF: +1, +3, +1, +1, +1.
- H is the 8th letter, so H + 3 = K, the 11th.
- The shift belongs to the position: A → D in 2nd place, A → B in 3rd place.
Study next
Common traps
- Reading A → D as a letter swap and turning CHAIR's A into D, when the shift belongs to the 2nd place
- Stopping at the first letter: D starts options (a), (c) and (d), so the second letter, H + 3 = K, is what decides
15 Sep 2025, 12:30, Reasoning Q.18 also changes the shift by position: FOLDER is GMLECR (+1, −2, 0 repeated), and MARKET is keyed NYRLCT.
19 Sep 2025, 09:00, Reasoning Q.18 uses one shift for every letter: GOAL is HPBM, so FAIL is keyed GBJM.
Related PYQs
No directly related past PYQ was found.