Find the missing number: 11 : 1452 :: 12 : ?
- (a)1872
- (b)1864
- (c)1850
- (d)1800
Answer
Why
Correct — A.
Rule: n → n² × (n + 1).
11² = 121
121 × 12 = 1452 ✓
12² = 144
144 × 13 = 1872 → option (a).
Why the others are wrong
- (b)1864 — 1864 is 8 short of 144 × 13. It is not a whole multiple of 144, so it cannot be 12² times a whole number.
- (c)1850 — 1850 falls between 144 × 12 = 1728 and 144 × 13 = 1872, so it is not a multiple of 144 at all.
- (d)1800 — 1800 is 144 × 12.5. The rule needs 12² × 13 = 1872, a whole-number multiple.
Concept
In a number analogy, work out how the second number is built from the first, then build the same way from the new number.
1452 is large next to 11, so try its powers. 11² = 121, and 1452 ÷ 121 = 12, one more than 11. So the pair is n² × (n + 1), which is also n³ + n²: 1331 + 121 = 1452.
The n³ + n² form gives a quick check for 12: 1728 + 144 = 1872. Divisibility works too: of the four options, 1872 is the one that 144 divides.
Key facts
- 11² = 121 and 11³ = 1331.
- 12² = 144 and 12³ = 1728.
- n² × (n + 1) = n³ + n².
Study next
Common traps
- Stopping at 1452 = 11 × 132 without seeing that 132 = 11 × 12
- Choosing 1864 for being close to 1872 instead of checking divisibility by 144
Here SSC pairs a two-digit number with a four-digit number built from its square and the next whole number.
Related PYQs
No directly related past PYQ was found.