The sum of two numbers is 40 and their difference is 4. What is the product of the numbers?
- (a)390
- (b)396
- (c)400
- (d)404
Answer
Why
Correct — B.
Rule: larger = (sum + difference) ÷ 2, smaller = (sum − difference) ÷ 2.
Larger: (40 + 4) ÷ 2 = 22
Smaller: (40 − 4) ÷ 2 = 18
Check: 22 + 18 = 40 and 22 − 18 = 4.
Product: 22 × 18 = 396 → option (b).
Why the others are wrong
- (a)390 — 390 is 6 below the true product. The sum 40 and difference 4 fix the pair at 22 and 18, and 22 × 18 is 396.
- (c)400 — 400 is 20 × 20, the product when the difference is 0. A difference of 4 splits 20 and 20 into 22 and 18, and the product drops to 396.
- (d)404 — 404 adds where the identity subtracts: (40² + 4²) ÷ 4 = 1616 ÷ 4 = 404. The product is (40² − 4²) ÷ 4 = 396.
Concept
Two numbers are fixed by their sum and difference. Adding the two facts cancels the smaller number, so the larger is (sum + difference) ÷ 2. Subtracting them cancels the larger, so the smaller is (sum − difference) ÷ 2.
For the product there is a shortcut: xy = [(x + y)² − (x − y)²] ÷ 4. Here (1600 − 16) ÷ 4 = 396, without finding the numbers at all.
Key facts
- The two numbers are 22 and 18.
- (x + y)² − (x − y)² = 4xy.
- For a fixed sum, the product is largest when the two numbers are equal: 20 × 20 = 400.
Study next
Common traps
- Adding the squares instead of subtracting them, (1600 + 16) ÷ 4 = 404
- Stopping at 20 × 20 because the sum splits evenly, which ignores the difference
12 Sep 2025, 16:00, Reasoning Q.18 also asks for two numbers from their sum, 64, but fixes them with a ratio, 3 : 5, keyed 24 and 40.
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