If 5 $ 2 = 27 and 7 $ 3 = 64, what is 6 $ 4?
- (a)10
- (b)12
- (c)8
- (d)14
Answer
Why
Correct — C.
Rule: a $ b = (a − b)³.
5 $ 2: (5 − 2)³ = 3³ = 27, as given
7 $ 3: (7 − 3)³ = 4³ = 64, as given
6 $ 4: (6 − 4)³ = 2³ = 8 → option (c).
Why the others are wrong
- (a)10 — 10 is 6 + 4, the plain sum. The sum fails the examples: 5 + 2 is 7, not 27. It is not a cube either, and both examples give cubes.
- (b)12 — 12 is not a cube. Both given results are cubes (27 = 3³, 64 = 4³), so the answer must be one too, and 12 lies between 2³ = 8 and 3³ = 27.
- (d)14 — 14 is not a cube, so no difference cubed produces it. With a − b = 2, the result has to be 2³ = 8.
Concept
A symbol puzzle hides an arithmetic rule. Find a rule that fits every example, then apply it once.
The results here, 27 and 64, are 3³ and 4³, and 3 and 4 are exactly the differences 5 − 2 and 7 − 3. Recognising the results as cubes is the fastest way in.
Test a candidate rule on both examples before using it. a² + b fits 5 $ 2 (25 + 2 = 27) but gives 52 for 7 $ 3, so it is out.
Key facts
- Cubes to memorise: 1, 8, 27, 64, 125, 216, 343, 512, 729, 1000.
- A rule is confirmed when it reproduces every given example, not just the first.
Study next
Common traps
- Stopping at a rule that fits the first example, such as a² + b, without testing the second.
- Picking 10 because it is the sum 6 + 4, a rule neither example supports.
14 Sep 2025, 12:30, Reasoning Q.18 asks for the same 6 $ 4 from different examples (9 $ 3 = 18, 8 $ 2 = 12). Its rule is (a − b) × b, and it is also keyed 8.
12 Sep 2025, 12:30, Reasoning Q.20 uses a² + b²: 7 $ 3 = 58 and 6 $ 2 = 40, keyed 26 for 5 $ 1.
Related PYQs
No directly related past PYQ was found.