In a cyclic quadrilateral ABCD, AB is the diameter of the circle. If angle ACD is 40°, what is the measure of angle BAD?
- (a)40°
- (b)50°
- (c)80°
- (d)90°
Answer
Why
Correct — B. Work in triangle ABD, using two circle facts.
∠ABD = ∠ACD = 40° (same segment: both stand on chord AD)
∠ADB = 90° (AB is a diameter: angle in a semicircle)
∠BAD = 180° − 90° − 40° = 50° → option (b)
Cross-check: ∠ACB = 90°, so ∠BCD = 90° + 40° = 130°, and the opposite angle ∠BAD = 180° − 130° = 50°.
Why the others are wrong
- (a)40° — 40° is ∠ABD, the angle equal to ∠ACD because both stand on chord AD. It sits at vertex B, not at A.
- (c)80° — 80° is double 40°, the angle chord AD subtends at the centre. ∠BAD is an angle at the circumference in triangle ABD, and it comes out as 50°.
- (d)90° — 90° is the angle in a semicircle. The diameter AB makes that right angle at D (∠ADB) and at C (∠ACB), not at A.
Concept
Angles in the same segment are equal: every point on one arc sees a chord at the same angle. So ∠ACD = ∠ABD.
The angle in a semicircle is 90°: any point on the circle sees a diameter at a right angle. So ∠ADB = ∠ACB = 90°.
The cross-check uses a third fact: opposite angles of a cyclic quadrilateral add to 180°.
The question gives no figure. The vertices of a cyclic quadrilateral ABCD are taken in order round the circle, which puts B and C on the same arc of chord AD.
Key facts
- Angles subtended by the same chord at points on the same arc are equal.
- The angle subtended by a diameter at any point of the circle is 90°.
- Opposite angles of a cyclic quadrilateral add to 180°.
- The angle a chord subtends at the centre is double the angle it subtends at a point on the major arc.
Study next
Common traps
- Stopping at ∠ABD = 40° and answering it, when the question asks for the angle at A.
- Doubling 40° to 80°, which is the angle at the centre, not at vertex A.
The same pairing of a diameter with a cyclic quadrilateral is asked at 19 Sep 2024, 12:30, Quant Q.2: PQ is a diameter and ∠PSR = 120°, so ∠QPR = 180° − 90° − 60° = 30°.
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