A common internal tangent connecting two circles is 9 cm long. The distance between the circles' centers is 15 cm. If the larger circle has a radius of 8 cm, what is the radius of the smaller circle?
- (a)4 cm
- (b)1 cm
- (c)6 cm
- (d)7 cm
Answer
Why
Correct — A. For a common internal (transverse) tangent, length² = d² − (r₁ + r₂)², with the radii added.
9² = 15² − (8 + r)²
81 = 225 − (8 + r)²
(8 + r)² = 225 − 81 = 144
8 + r = 12, so r = 4 cm → option (a)
Check: 8 + 4 = 12, less than 15, so the circles are apart and an internal tangent exists.
Why the others are wrong
- (b)1 cm — r = 1 cm makes r₁ + r₂ = 9, and √(15² − 9²) = √144 = 12 cm, not 9 cm. The 9 is the tangent length, not the sum of the radii.
- (c)6 cm — r = 6 cm makes r₁ + r₂ = 14, and √(225 − 196) = √29 ≈ 5.4 cm, not 9 cm.
- (d)7 cm — r = 7 cm makes r₁ + r₂ = 15, equal to the distance between the centres. The circles would touch externally, and √(225 − 225) gives an internal tangent of length 0.
Concept
Two separate circles have two kinds of common tangent. A direct (external) tangent keeps both circles on one side: length = √(d² − (r₁ − r₂)²).
A transverse (internal) tangent passes between them and crosses the line of centres: length = √(d² − (r₁ + r₂)²).
Both come from one right triangle. Slide the tangent parallel to itself through a centre: one leg becomes r₁ ± r₂ and the hypotenuse is d.
The direct-tangent formula cannot produce an answer here. (8 − r)² = 144 gives r = −4 or r = 20, and neither is a smaller radius. That is the sign you picked the wrong formula.
Key facts
- Direct common tangent: L = √(d² − (r₁ − r₂)²).
- Transverse common tangent: L = √(d² − (r₁ + r₂)²).
- Two transverse tangents need d > r₁ + r₂. At d = r₁ + r₂ the circles touch externally and those tangents merge into the tangent at the point of contact.
Study next
Common traps
- Using (r₁ − r₂)² from the direct-tangent formula. Here it gives r = 20 or −4, neither a smaller radius.
- Answering 15 − 8 = 7 cm, which would make the circles touch and the internal tangent zero.
The transverse tangent is asked directly at 24 Sep 2025, 12:30, Quant Q.21 (radii 6 and 2 cm, centres 10 cm apart). The direct tangent, with the same 15 cm and an 8 cm radius, is 23 Sep 2025, 16:00, Quant Q.21.
At 10 Sep 2024, 16:00, Quant Q.25 the two formulas are combined to find the product of the radii.
Related PYQs
No directly related past PYQ was found.