A sum becomes ₹12100 in 2 years at 10% Compound Interest annually. Find the principal.
- (a)₹10000
- (b)₹11000
- (c)₹11500
- (d)₹10500
Answer
Why
Correct — A. Compound interest multiplies the sum by (1 + r⁄100) each year.
Yearly factor = 1 + 10⁄100 = 1.1
Two years: 1.1 × 1.1 = 1.21
Set up: P × 1.21 = 12100
Divide: P = 12100 ÷ 1.21 = ₹10000 → option (a)
Check: ₹10000 → ₹11000 after year 1 → ₹12100 after year 2
Why the others are wrong
- (b)₹11000 — ₹11000 is the amount after the first year. Dividing 12100 by 1.1 undoes only one year of growth, and the sum grew for two.
- (c)₹11500 — ₹11500 × 1.21 = ₹13915, well past ₹12100, so this principal is too large.
- (d)₹10500 — ₹10500 × 1.21 = ₹12705, which overshoots ₹12100 by ₹605.
Concept
With annual compounding, A = P(1 + r⁄100)ⁿ. To recover the principal, divide the amount by the growth factor: P = A ÷ (1 + r⁄100)ⁿ.
At 10% the factors are worth knowing by heart: 1.1 for one year, 1.21 for two, 1.331 for three. 12100 = 1.21 × 10000, so the principal comes out round.
Key facts
- A = P(1 + r⁄100)ⁿ for interest compounded annually.
- At 10% a year the growth factor is 1.21 over 2 years and 1.331 over 3 years.
- Here the compound interest is 12100 − 10000 = ₹2100, against ₹2000 simple interest for the same 2 years.
Study next
Common traps
- Dividing by 1.1 once, which returns the amount after one year (₹11000), not the principal.
- Using simple interest: 12100 ÷ 1.2 ≈ ₹10083, which is not an option.
Amount, rate and time given, principal asked. The same 10% factor appears at 13 Sep 2025, 16:00, Quant Q.13, where ₹1,00,000 grows to ₹1,33,100 in 3 years, and a principal is recovered from two amounts at 12 Sep 2025, 09:00, Quant Q.11.
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