A train starts from a place Mumbai at 6 a.m. and arrives at Kolhapur at 2.30 p.m. on the same day. If the speed of the train is 60 km per hour, find the distance traveled by the train.

Correct — C. Find the travel time, then multiply by the speed.

Morning part, 6 a.m. to 12 noon: 12 − 6 = 6 h
Afternoon part, 12 noon to 2.30 p.m.: 2.5 h
Add the parts: 6 + 2.5 = 8.5 h
Distance = speed × time = 60 × 8.5 = 510 km → option (c)

Why the others are wrong

• (a)
  450 km — 450 km at 60 km/h takes 7.5 hours, a trip that would end at 1.30 p.m., an hour before the train actually reaches Kolhapur.
• (b)
  490 km — 490 km at 60 km/h takes 8 h 10 min, ending at 2.10 p.m. The train arrives at 2.30 p.m., twenty minutes later.
• (d)
  500 km — 500 km at 60 km/h takes 8 h 20 min, ending at 2.20 p.m., ten minutes before the stated arrival time.

Distance = speed × time, with the time in the unit the speed uses, here hours. The only real work is turning two clock readings into an elapsed time.

Across noon, split the interval at 12, or switch to 24-hour time: 14:30 − 06:00 = 8 h 30 min.

Thirty minutes is 0.5 h, not 0.3 h. On a clock, 2.30 means two and a half hours past noon.

Key facts

• Distance = speed × time.
• 2.30 p.m. is 14:30 in 24-hour time.
• 30 minutes = 0.5 hour.
• At 60 km/h, distance in km equals travel time in minutes.

Common traps

• Reading 2.30 as 2.3 hours, which gives 8.3 h and 498 km, a figure not among the choices.
• Subtracting the clock readings as printed: 2.30 p.m. minus 6 a.m. only works once 2.30 p.m. is written as 14:30.

No directly related past PYQ was found.