A regular hexagon has a perimeter of 72 cm. What is its area?
- (a)374.12 cm²
- (b)449.76 cm²
- (c)670.32 cm²
- (d)748.15 cm²
Answer
Why
Correct — A. A regular hexagon is six equilateral triangles of the same side.
Side = perimeter ÷ 6 = 72 ÷ 6 = 12 cm
One triangle = (√3⁄4) × 12² = 36√3 cm²
Hexagon = 6 × 36√3 = 216√3 cm²
Area ≈ 216 × 1.73205 ≈ 374.12 cm² → option (a)
Why the others are wrong
- (b)449.76 cm² — 449.76 cm² is the area of a regular hexagon of side about 13.2 cm, whose perimeter is about 79 cm, not 72 cm.
- (c)670.32 cm² — 670.32 cm² belongs to a hexagon of side about 16.1 cm, with a perimeter near 96 cm. It is far too large for a 72 cm perimeter.
- (d)748.15 cm² — 748.15 cm² is roughly double the true area. It is close to 3√3 × 12² ≈ 748.25, what you get if the ½ in (3√3⁄2)s² is dropped.
Concept
Joining the centre of a regular hexagon to its six corners cuts it into six equilateral triangles, each with the hexagon's side as its side.
So the area is 6 × (√3⁄4)s² = (3√3⁄2)s², about 2.598s².
The same picture explains why a regular hexagon inscribed in a circle has its side equal to the radius: each triangle's other two sides are radii.
Key facts
- Area of a regular hexagon = (3√3⁄2)s² ≈ 2.598s².
- Area of an equilateral triangle = (√3⁄4)s².
- Perimeter of a regular hexagon = 6s.
- √3 ≈ 1.732.
Study next
Common traps
- Using the perimeter, 72, as the side: (3√3⁄2) × 72² ≈ 13,468 cm², nowhere near the options.
- Dropping the ½ in (3√3⁄2)s², which roughly doubles the answer.
The same six-triangle formula settles 21 Sep 2025, 16:00, Quant Q.9, where the hexagon sits inside a circle of radius 14 cm, so s = 14 and the area is (3√3⁄2) × 196 ≈ 509.2 cm².
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