If in a code language, 'CAR' is written as 'FDW', then 'BAT' is written as?
- (a)EDY
- (b)GEX
- (c)FCX
- (d)FBY
Answer
Why
Correct — A.
Rule: read the shift at each position: +3, +3, +5.
C (3) → F (6): +3
A (1) → D (4): +3
R (18) → W (23): +5
B (2) + 3 = E (5)
A (1) + 3 = D (4)
T (20) + 5 = Y (25)
BAT → EDY → option (a).
Why the others are wrong
- (b)GEX — GEX moves B five places to G. The first position moves +3, as C → F shows, so B becomes E.
- (c)FCX — FCX moves B four places and A two. The pair CAR → FDW fixes +3 for both of the first two letters: E and D.
- (d)FBY — FBY gets the last letter right (T + 5 = Y) but moves A only one place. The second position moves +3, so A becomes D.
Concept
A code given by a single pair can shift each position by a different amount, so work out the shift letter by letter before applying it. Here the first two letters move +3 and the third moves +5.
Assuming one shift for the whole word would give B + 3, A + 3, T + 3 = EDW, which is not among the options. That is the signal to look again at the third letter.
The stem gives one pair, so the +3, +3, +5 reading is what it supports. Checked against that reading, EDY fits at all three positions and each of the other options fails at least one.
Key facts
- C → F and A → D are shifts of +3, and R → W is a shift of +5.
- B + 3 = E, A + 3 = D, T + 5 = Y.
- A uniform +3 would give EDW, which is not offered.
Study next
Common traps
- Checking only the first letter's shift and applying +3 throughout.
- Taking FBY because its last letter, Y, is right, when its first two letters move +4 and +1.
A uniform +3 code is set at 24 Sep 2025, 12:30, Reasoning Q.25 (PEARL → SHDUO, so STONE → VWRQH), where every letter moves the same three places.
Related PYQs
No directly related past PYQ was found.