A circular jogging track has a radius of 50 m. A runner covers a curved path that subtends an angle of 120° at the center. What is the length of the arc she runs?
- (a)100π⁄3 m
- (b)150π⁄3 m
- (c)200π⁄3 m
- (d)200π⁄3 m
Answer
Why
Correct — A.
Arc length = (θ⁄360°) × 2πr
= (120⁄360) × 2π × 50
= (1⁄3) × 100π
= 100π⁄3 m → option (a).
Check: 120° is one third of 360°, so the arc is a third of the 100π m track.
Why the others are wrong
- (b)150π⁄3 m — 150π⁄3 m is 50π m, the arc for 180°, half the 100π m track. 120° is a third of the circle, not half.
- (c)200π⁄3 m — 200π⁄3 m is the major arc, (240⁄360) × 100π, the part of the track she does not run. Putting the diameter 100 m in place of the radius gives the same wrong value.
- (d)200π⁄3 m — Printed identically to (c). 200π⁄3 m is double the right arc: the 240° major arc, or the formula run with the diameter instead of the radius.
Concept
An arc takes the same fraction of the circumference as its angle takes of 360°. The track's circumference is 2π × 50 = 100π m, and 120° is a third of 360°, so the arc is a third of 100π.
In radians the same rule reads ℓ = rθ: 120° = 2π⁄3, and 50 × 2π⁄3 = 100π⁄3.
Options (c) and (d) are printed identically on the response sheet, both 200π⁄3 m. Neither is the key, so the duplicate does not change the answer.
Key facts
- Arc length = (θ⁄360°) × 2πr.
- In radians, arc length = rθ, and 120° = 2π⁄3 rad.
- Sector area = (θ⁄360°) × πr², which also equals ½ × r × arc length.
- 100π⁄3 m ≈ 104.7 m.
Study next
Common traps
- Putting the diameter, 100 m, into 2πr. That doubles the arc to 200π⁄3 m.
- Reaching for the sector-area formula (θ⁄360°) × πr², which gives 2500π⁄3 m², an area rather than a length.
The same (θ⁄360°) × 2πr step is keyed at 12 Sep 2024, 16:00, Quant Q.25 (radius 9.6, 75° → 4π). 12 Sep 2024, 16:00, Quant Q.20 adds the two radii to ask for a sector's perimeter (radius 12 cm, 30° → 30.28 cm).
Related PYQs
No directly related past PYQ was found.