Two numbers are in the ratio 6:5. If the difference between them is 11, find the numbers.
- (a)66 and 55
- (b)60 and 49
- (c)72 and 61
- (d)88 and 77
Answer
Why
Correct — A. Write the two numbers as 6k and 5k for some multiplier k.
Difference: 6k − 5k = k
Set it equal to 11: k = 11
Numbers: 6 × 11 = 66 and 5 × 11 = 55 → option (a)
Check: 66 : 55 reduces to 6 : 5 on dividing by 11, and 66 − 55 = 11.
Why the others are wrong
- (b)60 and 49 — The difference is 11, but 60 : 49 is not 6 : 5. With 60 as the 6-part, the 5-part would have to be 50.
- (c)72 and 61 — The difference is 11, but 72 : 61 is not 6 : 5. With 72 as the 6-part, the 5-part would have to be 60.
- (d)88 and 77 — The difference is 11, but 88 : 77 reduces to 8 : 7 on dividing by 11, not 6 : 5.
Concept
A ratio a : b fixes the proportion, not the size, so write the quantities as ak and bk for an unknown multiplier k.
A stated total or difference then pins k. Here the difference is (6 − 5)k = k, so the difference itself is the multiplier.
In general, with difference D, k = D ⁄ (a − b).
All four options differ by exactly 11, so checking the difference eliminates nothing. The ratio check is what separates them.
Key facts
- Numbers in the ratio a : b can be written as ak and bk.
- If their difference is D, then k = D ⁄ (a − b).
- If their sum is S, then k = S ⁄ (a + b).
- To test a pair, divide both by their HCF: 66 and 55 share 11 and leave 6 and 5.
Study next
Common traps
- Checking the difference alone: every option here differs by 11.
- Taking 11 as one of the numbers instead of as the multiplier k.
Here the difference is given and both numbers are asked. A two-term ratio with a given difference is also set at 24 Sep 2024, 16:00, Quant Q.13 (2 : 5, difference 210), and a three-term ratio with a given average at 20 Sep 2025, 12:30, Quant Q.17.
Related PYQs
No directly related past PYQ was found.