Ajay and Vijay start from the same point and walk at 4 km/h and 5 km/h respectively, in the same direction. What will be the distance between them after 2 hours?
- (a)2.5 km
- (b)3 km
- (c)2 km
- (d)4 km
Answer
Why
Correct — C. Walking the same way, the gap between them grows at the difference of their speeds.
Relative speed: 5 − 4 = 1 km/h
Gap after 2 hours: 1 × 2 = 2 km → option (c)
Check with distances: Vijay walks 5 × 2 = 10 km, Ajay walks 4 × 2 = 8 km, and 10 − 8 = 2 km.
Why the others are wrong
- (a)2.5 km — 2.5 km would need the gap to widen at 1.25 km/h for 2 hours. The speeds differ by exactly 1 km/h.
- (b)3 km — 3 km is the gap after 3 hours. At 1 km/h the gap in km equals the hours walked, and they walk for 2.
- (d)4 km — 4 km would need the gap to widen at 2 km/h, twice the real rate of 5 − 4 = 1 km/h.
Concept
Two walkers leaving one point together start with a gap of zero. After that the gap changes at their relative speed.
Same direction: relative speed = difference of the speeds, because each hour the faster walker pulls ahead by that much.
Opposite directions: relative speed = sum of the speeds.
Gap = relative speed × time, so here the gap in km equals the hours walked.
Had they walked in opposite directions, the gap would be (4 + 5) × 2 = 18 km, which is not among the options. The words "in the same direction" decide the setup.
Key facts
- Same direction: relative speed = difference of the two speeds.
- Opposite directions: relative speed = sum of the two speeds.
- For two people starting together from one point, distance apart = relative speed × time.
Study next
Common traps
- Adding the speeds because both are moving: that is the rule for opposite directions and gives 18 km here.
- Stopping at the faster walker's 10 km and forgetting to subtract Ajay's 8 km.
Here the setup is bare: a common start, two speeds, one direction.
Same-direction and towards-each-other relative speeds are combined at 12 Sep 2025, 09:00, Quant Q.20 (two cars 360 km apart) and 20 Sep 2025, 09:00, Quant Q.5 (a thief and a police officer 500 m apart).
Related PYQs
No directly related past PYQ was found.