What is the length of the segment joining (1,2) and (4,6)?
- (a)5
- (b)2
- (c)4
- (d)3
Answer
Why
Correct — A. Use the distance formula: d = √((x₂ − x₁)² + (y₂ − y₁)²).
Horizontal gap: 4 − 1 = 3
Vertical gap: 6 − 2 = 4
Square and add: 3² + 4² = 9 + 16 = 25
Square root: d = √25 = 5 → option (a)
Why the others are wrong
- (b)2 — 2 is shorter than both gaps. The segment is the hypotenuse of a right triangle with legs 3 and 4, and a hypotenuse is always longer than either leg.
- (c)4 — 4 is the vertical gap alone, 6 − 2. That is one leg of the right triangle, and the slanted segment joining the points is longer than either leg.
- (d)3 — 3 is the horizontal gap alone, 4 − 1. Stopping there drops the rise of 4 units, and both gaps go into the formula as squares.
Concept
The distance formula is Pythagoras on a grid. Joining (x₁, y₁) to (x₂, y₂), the horizontal gap and the vertical gap are the two legs of a right triangle, and the segment is its hypotenuse.
So d² = (x₂ − x₁)² + (y₂ − y₁)². The order of subtraction does not matter, because each gap is squared.
Here the legs are 3 and 4, the 3-4-5 triple, so the length is a whole number.
The three wrong options are 2, 4 and 3, none longer than the longer leg. Knowing that a hypotenuse is longer than both legs settles the item before any squaring.
Key facts
- Distance between (x₁, y₁) and (x₂, y₂) = √((x₂ − x₁)² + (y₂ − y₁)²).
- The horizontal and vertical gaps are the legs of a right triangle, and the segment is its hypotenuse.
- 3, 4, 5 is a Pythagorean triple: 3² + 4² = 5².
Study next
Common traps
- Reporting one of the gaps, 3 or 4, as the length instead of combining both.
- Squaring and adding to 25 but forgetting the square root.
Coordinate geometry also appears on 21 Sep 2025, 16:00, Quant Q.23, where P is equidistant from A(0, 0), B(4, 0) and C(0, 3): the same 3-4-5 triangle, and the keyed point (2, 1.5) is the midpoint of the 5-unit side BC.
18 Sep 2025, 09:00, Quant Q.16 asks for the midpoint of (3,4) and (7,8) instead of the length.
Related PYQs
No directly related past PYQ was found.