A company designs a new chocolate box in the shape of a regular right pyramid with a square base. The base side of the box is 10 cm and its height is 12 cm. Due to packaging constraints, the box can only be filled up to 90% of its total volume. If the company wants to estimate the total cost of chocolate, knowing that 1 cm³ of chocolate costs ₹0.50, what is the cost of chocolate to fill one such box?
- (a)₹180
- (b)₹225
- (c)₹270
- (d)₹300
Answer
Why
Correct — A. Volume of a pyramid = ⅓ × base area × height.
Base area = 10 × 10 = 100 cm²
Full volume = ⅓ × 100 × 12 = 400 cm³
Filled to 90% = 0.9 × 400 = 360 cm³
Cost = 360 × ₹0.50 = ₹180 → option (a)
Why the others are wrong
- (b)₹225 — ₹225 buys 225 ÷ 0.50 = 450 cm³ of chocolate. The full box holds only 400 cm³, and just 360 cm³ can go in.
- (c)₹270 — ₹270 is what ½ in place of ⅓ gives: ½ × 100 × 12 = 600 cm³, 90% of that is 540 cm³, and 540 × ₹0.50 = ₹270.
- (d)₹300 — ₹300 pays for 600 cm³, which is ½ × 100 × 12 with no 90% cut. The whole box holds only 400 cm³.
Concept
A pyramid holds exactly one third of the prism on the same base and height. A 10 × 10 × 12 cuboid holds 1200 cm³, so the pyramid holds 400 cm³.
After that the 90% limit and the price per cm³ are plain percentage and rate steps. Stay in cm³ until the last line, then convert to rupees once.
The slant height, √(5² + 12²) = 13 cm, is not needed. Volume uses the vertical height, which the question gives as 12 cm.
Key facts
- Volume of a pyramid = ⅓ × base area × vertical height.
- A pyramid holds one third of the prism with the same base and height.
- For this square pyramid (base 10 cm, height 12 cm) the slant height is √(5² + 12²) = 13 cm.
Study next
Common traps
- Using ½ instead of ⅓ in the volume formula, which turns ₹180 into ₹270.
- Putting the slant height (13 cm) in place of the vertical height (12 cm).
The ⅓ rule is asked bare at 15 Sep 2025, 09:00, Quant Q.17 (base area 60 cm², height 9 cm, volume 180 cm³).
A square base given by its diagonal comes up in Tier-II Paper-I, 19 Jan 2026, 11:00, Quant Q.24 (diagonal √512 m, height 8 m, about 683 m³).
Related PYQs
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