A person invested ₹8,000 in one scheme at 6% simple interest and ₹5,000 in another scheme at 8% simple interest for the same duration. If he received a total interest of ₹1,760 from both investments, what was the duration (time period) of the investments?
- (a)1 year
- (b)2 years
- (c)2.5 years
- (d)3 years
Answer
Why
Correct — B.
One year on ₹8,000 at 6%: 8000 × 6 ÷ 100 = ₹480
One year on ₹5,000 at 8%: 5000 × 8 ÷ 100 = ₹400
Add them: 480 + 400 = ₹880 a year
Divide the total interest by one year's interest: 1760 ÷ 880 = 2
So the duration is 2 years → option (b)
Why the others are wrong
- (a)1 year — One year earns only ₹880 from both schemes together, which is half of the ₹1,760 received.
- (c)2.5 years — 2.5 years earns 880 × 2.5 = ₹2,200, which is ₹440 more than the ₹1,760 received.
- (d)3 years — 3 years earns 880 × 3 = ₹2,640, one and a half times the ₹1,760 received.
Concept
When several sums earn simple interest for the same time, the time is a common factor: total SI = (P₁R₁ + P₂R₂) × T ÷ 100.
So find one year's interest from all the sums together, then divide the total interest by it to get the number of years.
Here one year brings ₹880, and ₹1,760 is exactly two years' worth.
Check each scheme on its own for 2 years: ₹8,000 at 6% earns ₹960 and ₹5,000 at 8% earns ₹800, and 960 + 800 = ₹1,760.
Key facts
- Simple interest grows in step with time: two years earn twice one year's interest
- For sums invested for the same time, total SI = (P₁R₁ + P₂R₂) × T ÷ 100
- ₹8,000 at 6% and ₹5,000 at 8% earn ₹880 a year together
Study next
Common traps
- Averaging 6% and 8% to 7% on the whole ₹13,000. The sums are unequal, so the blended rate is 880 ÷ 13,000 ≈ 6.77%, not 7%
12 Sep 2025, 16:00, Quant Q.20 pools two loans the same way but asks for the rate: 5000 × 2 + 3000 × 4 = 22000, and 22000 × R ÷ 100 = 2200 makes R = 10%.
24 Sep 2024, 16:00, Quant Q.12 asks for a principal instead: (3000 + x) × 8 × 5 ÷ 100 = 1600 gives x = ₹1,000.
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