Solve: AC : DF :: GI : ?
- (a)JL
- (b)KM
- (c)LN
- (d)MO
Answer
Why
Correct — A.
Rule: each letter moves +3.
A (1) + 3 = D (4), C (3) + 3 = F (6): AC → DF
G (7) + 3 = J (10), I (9) + 3 = L (12)
GI → JL → option (a).
Why the others are wrong
- (b)KM — KM moves each letter +4: G (7) → K (11), I (9) → M (13). The given pair moves +3, A → D.
- (c)LN — LN is a +5 shift, G → L and I → N. AC → DF fixes the step at +3, which gives J and L.
- (d)MO — MO is a +6 shift, G → M and I → O, double the +3 that takes A to D.
Concept
Letter analogies are solved with alphabet positions: A = 1, B = 2 … Z = 26. Write the number under each letter and read the change from the first pair.
Two patterns are in play. Inside each pair the letters sit two apart (A_C, D_F, G_I). From one pair to the next, every letter moves +3.
All four options keep the two-apart gap, so the +3 shift is what separates them.
The four pairs also run as a series, AC, DF, GI, JL, each starting three letters after the one before.
Key facts
- Alphabet positions: A 1, D 4, G 7, J 10, M 13.
- AC → DF is a +3 shift on both letters.
- Every option keeps its letters two apart, so that gap cannot decide the answer.
Study next
Common traps
- Seeing the two-apart gap inside each pair and missing the +3 shift between pairs
- Miscounting a position: J is the 10th letter, K the 11th
17 Sep 2025, 16:00, Reasoning Q.13 is the same fixed shift with a bigger step: AB : IJ moves each letter +8, so EF becomes MN.
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