If every exterior angle of a regular polygon is 60°, how many sides does the polygon have?
- (a)4
- (b)5
- (c)6
- (d)8
Answer
Why
Correct — C.
The exterior angles of a polygon, one at each vertex, add up to 360°
In a regular polygon all n of them are equal, so each is 360° ÷ n
Solve: n = 360° ÷ 60° = 6
Check: interior angle = 180° − 60° = 120°, the angle of a regular hexagon → option (c)
Why the others are wrong
- (a)4 — A square's exterior angles are 90° each (360° ÷ 4). A 60° exterior angle needs more sides than four.
- (b)5 — A regular pentagon's exterior angle is 72° (360° ÷ 5), with interior angles of 108°. That is larger than 60°, so five sides are too few.
- (d)8 — A regular octagon's exterior angle is 45° (360° ÷ 8), with interior angles of 135°. That is smaller than 60°, so eight sides are too many.
Concept
Walking once round a convex polygon, you turn through one full turn, 360°. Each turn is the exterior angle at a vertex, so the exterior angles add up to 360° whatever the number of sides.
In a regular n-sided polygon they are equal: each is 360° ÷ n. Turned round, n = 360° ÷ exterior angle.
The interior angle is the supplement: 180° − exterior angle.
Key facts
- Sum of the exterior angles of a convex polygon, one per vertex = 360°
- Each exterior angle of a regular n-sided polygon = 360° ÷ n
- Each interior angle of a regular n-sided polygon = (n − 2) × 180° ÷ n
Study next
Common traps
- Treating 60° as the interior angle, which describes an equilateral triangle with 3 sides
- Dividing 180° instead of 360° by the exterior angle
21 Sep 2025, 09:00, Quant Q.22 is the same step with a 20° exterior angle, keyed 18 sides. 19 Sep 2025, 16:00, Quant Q.18 gives the interior angle, 150°, so the exterior angle is 30° and the key is 12.
Related PYQs
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