A prism has an equilateral triangular base with a side length of 4 cm. Its height starts at 5 cm and increases by 1 cm for each subsequent layer, forming 5 layers in total. What is the total volume of the prism? (Use √3≈1.732)
- (a)207.84 cm³
- (b)242.48 cm³
- (c)259.80 cm³
- (d)303.10 cm³
Answer
Why
Correct — B.
Base area, equilateral triangle of side 4: (√3⁄4) × 4² = 4√3 cm²
Layer heights: 5, 6, 7, 8, 9 cm
Add them: 5 + 6 + 7 + 8 + 9 = 35 cm
Volume = base area × total height = 4√3 × 35 = 140√3 cm³
Use √3 ≈ 1.732: 140 × 1.732 = 242.48 cm³ → option (b)
Why the others are wrong
- (a)207.84 cm³ — 207.84 cm³ is 120 × 1.732, which is 4√3 × 30, a total height of 30 cm. The five layers add to 35 cm, not 30.
- (c)259.80 cm³ — 259.80 cm³ is 150 × 1.732, which is 4√3 × 37.5, a total height of 37.5 cm. Five layers rising from 5 cm by 1 cm add to 35 cm.
- (d)303.10 cm³ — 303.10 cm³ is 175 × 1.732, which is 4√3 × 43.75, a total height of 43.75 cm. That is 8.75 cm more than the 35 cm the five layers stack to.
Concept
A prism's volume is base area × height. Layers that share one base simply add, so you can add the heights first and multiply once.
The heights 5, 6, 7, 8, 9 form an arithmetic progression. Its sum is n⁄2 × (first + last) = 5⁄2 × (5 + 9) = 35.
The base is an equilateral triangle, so its area is (√3⁄4)a², not ½ × a × a.
The stem's "layers" are read as five stacked pieces on the same triangular base, with heights 5 to 9 cm. That reading gives the keyed 242.48 cm³. One prism of final height 9 cm would give about 62.35 cm³, which is not among the options.
Key facts
- Volume of a prism = base area × height
- An equilateral triangle of side 4 cm has area 4√3 ≈ 6.928 cm²
- Sum of an arithmetic progression = n⁄2 × (first term + last term)
Study next
Common traps
- Using the last layer's height, 9 cm, alone, which gives about 62.35 cm³
- Taking the base as ½ × 4 × 4 = 8 cm², a right triangle's area, instead of (√3⁄4) × 4²
20 Sep 2025, 09:00, Quant Q.15 builds the same kind of prism on a 5 cm square base with heights 4, 8, 12, 16 cm, keyed 1000 cm³ (25 × 40).
18 Sep 2025, 09:00, Quant Q.15 stacks pieces of 5, 7, 9, 11 cm on a regular hexagon of side 10 cm, keyed 4800√3 cm³.
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