A bag contains ₹5, ₹2, and ₹1 coins in the ratio 2 : 3 : 4. If the total amount of money in the bag is ₹200, find the number of coins of each kind.
- (a)16 coins of ₹5, 24 coins of ₹2, and 32 coins of ₹1
- (b)20 coins of ₹5, 30 coins of ₹2, and 40 coins of ₹1
- (c)25 coins of ₹5, 35 coins of ₹2, and 45 coins of ₹1
- (d)18 coins of ₹5, 27 coins of ₹2, and 36 coins of ₹1
Answer
Why
Correct — B. Write the coin counts as 2k, 3k and 4k, then add up their value.
₹5 coins: 2k × 5 = 10k
₹2 coins: 3k × 2 = 6k
₹1 coins: 4k × 1 = 4k
Total value: 10k + 6k + 4k = 20k
Set 20k = 200, so k = 10
Counts: 2 × 10, 3 × 10, 4 × 10 = 20, 30, 40 → option (b)
Why the others are wrong
- (a)16 coins of ₹5, 24 coins of ₹2, and 32 coins of ₹1 — This is k = 8, so the value is 16 × 5 + 24 × 2 + 32 × 1 = 80 + 48 + 32 = ₹160, not ₹200.
- (c)25 coins of ₹5, 35 coins of ₹2, and 45 coins of ₹1 — 25 : 35 : 45 = 5 : 7 : 9, not 2 : 3 : 4. Its value, 125 + 70 + 45 = ₹240, misses ₹200 as well.
- (d)18 coins of ₹5, 27 coins of ₹2, and 36 coins of ₹1 — This is k = 9, which gives 90 + 54 + 36 = ₹180, ₹20 short. Each unit of k adds ₹20, so ₹200 needs k = 10.
Concept
A ratio of coin counts is not a ratio of values. Multiply each share by the coin's face value first.
Counts 2 : 3 : 4 of ₹5, ₹2 and ₹1 coins give values 10 : 6 : 4, which is 20 parts.
Split ₹200 in 10 : 6 : 4: ₹100, ₹60 and ₹40.
Divide by face value: 100 ÷ 5 = 20, 60 ÷ 2 = 30, 40 ÷ 1 = 40 coins.
Three options are exact multiples of 2 : 3 : 4 (k = 8, 10 and 9), so the ratio alone cannot pick the answer. The ₹200 total decides it.
Key facts
- Value of a coin group = number of coins × face value.
- Counts 2 : 3 : 4 of ₹5, ₹2 and ₹1 coins give values 10 : 6 : 4.
- Each unit of k here adds ₹20 to the bag (10 + 6 + 4).
Study next
Common traps
- Dividing ₹200 in the ratio 2 : 3 : 4 directly, which splits the money, not the coins.
- Checking only that an option keeps the 2 : 3 : 4 ratio, which options (a) and (d) also do.
Also asked 10 Sep 2024, 09:00, Quant Q.13, with one-rupee, 5-rupee and 10-rupee coins in the ratio 3 : 5 : 7 and ₹980 in the bag. There each k is worth 3 + 25 + 70 = ₹98, so k = 10 and the bag holds 70 coins of ₹10.
Related PYQs
No directly related past PYQ was found.