A statement is given followed by two conclusions. Find which conclusion is TRUE based on the given statement. Statement: C ≥ T ; A = D ≥ O; G ≥ D < S; T ≥ A Conclusions: I: A ≤ O II: C ≥ G

Correct — D.
Rule: a conclusion is definite only if one chain joins its two letters with all signs pointing one way.

The statement joins into C ≥ T ≥ A = D ≥ O, with G ≥ D < S hanging off D.

I (A ≤ O): the chain gives A ≥ O, so A ≤ O holds only if A = O. Not definite.
II (C ≥ G): C and G both sit above D, and nothing compares them. Not definite.

The two compare different letters, so either–or cannot apply.
Neither → option (d).

Why the others are wrong

• (a)
  Either I or II — Either I or II needs two conclusions about the same pair that cover every case between them. I compares A with O and II compares C with G, so it cannot apply.
• (b)
  Only II — C ≥ G is not given. C ≥ T ≥ A = D puts C above D, and G ≥ D puts G above D, but no sign compares C with G.
• (c)
  Only I — A ≤ O runs against the chain. A = D ≥ O makes A at least O, so A ≤ O is true only in the special case A = O.

Inequality items are solved by joining the pieces into one chain. Here C ≥ T, T ≥ A and A = D ≥ O link into C ≥ T ≥ A = D ≥ O, while G ≥ D < S hangs off D.

Two letters are comparable only if the chain between them runs one way, all ≥ (or =) or all ≤. C to D runs downward but D to G runs upward, so C and G cannot be compared.

Key facts

• A chain gives a definite result only when all its signs point the same way.
• A ≥ B with B ≥ C gives A ≥ C, but A ≥ B with C ≥ B gives no relation between A and C.
• Either–or needs both conclusions to compare the same two letters and to cover every case between them.

Common traps

• Reading A = D ≥ O backwards and accepting A ≤ O
• Linking C and G through D, when the signs on either side of D point in opposite directions
• Choosing Either I or II because both conclusions fail, without checking that they compare the same pair

No directly related past PYQ was found.