Solve:(√7225−√1225) × (1⁄5)
- (a)10
- (b)20
- (c)30
- (d)40
Answer
Why
Correct — A. Take each square root, subtract, then multiply by 1⁄5.
√7225 = 85, since 85² = 7225
√1225 = 35, since 35² = 1225
Subtract: 85 − 35 = 50
Multiply by 1⁄5: 50 × 1⁄5 = 10 → option (a)
Why the others are wrong
- (b)20 — 20 would need the bracket to equal 100. It is 85 − 35 = 50, and 50 × 1⁄5 = 10.
- (c)30 — 30 would need the bracket to equal 150. √7225 − √1225 = 85 − 35 = 50, so the product is 10.
- (d)40 — 40 would need the bracket to equal 200, four times the true 85 − 35 = 50.
Concept
A perfect square ending in 25 has a root ending in 5, and (10n + 5)² = 100 × n(n + 1) + 25.
So read the digits before 25:
7225 → 72 = 8 × 9, so √7225 = 85
1225 → 12 = 3 × 4, so √1225 = 35
A root does not split over subtraction: √7225 − √1225 is not √(7225 − 1225).
Both numbers under the roots are perfect squares, so no approximation is needed. The (1⁄5) is a separate factor, applied after the subtraction.
Key facts
- (10n + 5)² = 100 × n(n + 1) + 25, so 85² = 7225 and 35² = 1225.
- √a − √b is not equal to √(a − b).
- Multiplying by 1⁄5 is the same as dividing by 5.
Study next
Common traps
- Subtracting first and rooting after: √(7225 − 1225) = √6000 ≈ 77.46, which gives about 15.5, not an option.
- Guessing √1225 from its last digits alone. Every root ending in 5 squares to a number ending in 25, so check 35² = 1225 first.
Roots of perfect squares are also asked 18 Sep 2025, 12:30, Quant Q.2, where √289 = 17, √144 = 12 and √400 = 20 unwind a nested root to 20.
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