Find the odd one out:
- (a)6 # 2 = 12
- (b)5 # 3 = 15
- (c)4 # 4 = 16
- (d)7 # 1 = 21
Answer
Why
Correct — D.
Rule: a # b = a × b.
6 # 2: 6 × 2 = 12, as given
5 # 3: 5 × 3 = 15, as given
4 # 4: 4 × 4 = 16, as given
7 # 1: 7 × 1 = 7, but it says 21
7 # 1 = 21 breaks the rule → option (d).
Why the others are wrong
- (a)6 # 2 = 12 — 6 # 2 = 12 fits the product rule, 6 × 2 = 12. It is one of the three that agree.
- (b)5 # 3 = 15 — 5 # 3 = 15 fits: 5 × 3 = 15, the same rule that (a) and (c) follow.
- (c)4 # 4 = 16 — 4 # 4 = 16 fits: 4 × 4 = 16. Two equal numbers make it look different, but the product still holds.
Concept
In an odd-one-out built on a made-up symbol, the symbol hides one rule that three options obey. Find a rule that fits three and check it on the fourth.
Here the three results are exactly the products. 21 is 3 × 7, so 7 # 1 would need a different rule from the rest.
Make sure no other rule fits a different three. None does here: a rule such as 3 × a × b would give 7 # 1 = 21, but it makes 6 # 2 = 36, not 12.
Key facts
- 6 × 2 = 12, 5 × 3 = 15 and 4 × 4 = 16.
- 7 × 1 = 7, so 7 # 1 = 21 breaks the product rule.
- An odd-one-out rule must hold for exactly three of the four options.
Study next
Common traps
- Picking 4 # 4 = 16 because its two numbers are equal
- Stopping at the first option that fits instead of testing all four
15 Sep 2025, 12:30, Reasoning Q.9 sets the same odd-one-out with @: three options obey a @ b = 2 × (a + b), and 7 @ 1 = 14 breaks it (keyed b).
Related PYQs
No directly related past PYQ was found.