A circle with radius x touches another circle with radius 2x externally. What is the length of a direct common tangent?
- (a)2x
- (b)3x
- (c)2x√2
- (d)3x√2
Answer
Why
Correct — C. Circles that touch externally have their centres r₁ + r₂ apart.
Centre distance: d = x + 2x = 3x
Direct tangent: L² = d² − (r₁ − r₂)²
Substitute: L² = (3x)² − (2x − x)² = 9x² − x² = 8x²
Take the root: L = √8 × x = 2x√2 → option (c)
Why the others are wrong
- (a)2x — 2x is too short: (2x)² = 4x², only half of L² = 9x² − x² = 8x². It is the correct 2x√2 with the √2 dropped.
- (b)3x — 3x is the distance between the centres, x + 2x. A direct tangent equals that distance only when the radii are equal; here they differ by x, so L² = 9x² − x².
- (d)3x√2 — 3x√2 ≈ 4.24x is longer than the 3x between the centres. A direct common tangent can never exceed the centre distance, because L² = d² − (r₁ − r₂)².
Concept
Direct common tangent: both circles lie on the same side of it. The radii to its touching points are both perpendicular to it, hence parallel.
A line through the smaller centre, parallel to the tangent, forms a right triangle: hypotenuse d, legs L and r₁ − r₂.
So L² = d² − (r₁ − r₂)². When the circles touch externally, d = r₁ + r₂, and this collapses to L = 2√(r₁r₂).
Shortcut check: 2√(x × 2x) = 2√(2x²) = 2x√2, the same answer without finding d.
A transverse common tangent crosses between the circles, and its leg is r₁ + r₂: M² = d² − (r₁ + r₂)². For circles that touch externally M = 0, because both touching points are the point of contact.
Key facts
- Direct common tangent: L = √(d² − (r₁ − r₂)²).
- Transverse common tangent: M = √(d² − (r₁ + r₂)²).
- Circles touching externally: d = r₁ + r₂, so L = 2√(r₁r₂).
Study next
Common traps
- Putting r₁ + r₂ into the direct-tangent formula, which gives 9x² − 9x² = 0.
- Answering the centre distance 3x instead of the tangent length.
16 Sep 2025, 09:00, Quant Q.23 asks for the shortcut itself: circles touching externally have a direct common tangent T = 2√(r₁r₂).
15 Sep 2025, 09:00, Quant Q.22 runs the formula backwards: radii 12 cm and 4 cm with a 15 cm tangent give d² = 15² + 8² = 289, so d = 17 cm.
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