In a 40 L solution, the ratio of acid to water is 5:3. How much water must be added to make it 1:1?
- (a)5 L
- (b)6 L
- (c)17 L
- (d)10 L
Answer
Why
Correct — D.
Rule: only water is added, so the acid stays fixed.
Acid = 5⁄8 × 40 = 25 L
Water = 3⁄8 × 40 = 15 L
For 1:1, water must equal acid = 25 L
Water to add = 25 − 15 = 10 L → option (d).
Why the others are wrong
- (a)5 L — 5 L takes the water to 20 L against 25 L of acid, a ratio of 5:4. The mixture is still acid-heavy.
- (b)6 L — 6 L takes the water to 21 L against 25 L of acid, 25:21. Water must reach 25 L to match the acid.
- (c)17 L — 17 L overshoots: water becomes 32 L against 25 L of acid, so the mixture ends up with more water than acid.
Concept
In a dilution problem the component you do not add stays fixed. Split the 40 L by the ratio 5:3, which is 8 parts of 5 L each, to get 25 L of acid and 15 L of water.
A 1:1 ratio needs water equal to acid, so the water must rise from 15 L to 25 L. The difference is what you add.
The parts route is quicker. Acid is 5 parts and stays 5. For 1:1 the water must also be 5 parts. It is 3 now, so add 2 parts, and one part is 40 ÷ 8 = 5 L, giving 10 L.
Key facts
- 40 L in the ratio 5:3 is 25 L acid and 15 L water (one part = 5 L).
- Adding water changes only the water, so the acid stays 25 L.
- At 1:1 the mixture holds 25 L of each, 50 L in all.
Study next
Common traps
- Making the water half of the original 40 L (20 L) and adding 5 L, forgetting that the total grows
- Adding 25 L, the acid amount, instead of the difference 25 − 15
23 Sep 2024, 09:00, Quant Q.20 is the same set-up with milk: 32 L at 5:3, water added until it is 50%, keyed 8 litres.
14 Sep 2025, 16:00, Quant Q.11 runs it backwards: acid and water at 5:3 become 5:4 after 4 L of water, keyed original acid 20 litres.
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