If each letter is coded as its position in reverse (Z=1, Y=2,...A=26), what is ROAD?
- (a)10, 12, 25, 23
- (b)9, 12, 25, 23
- (c)9, 13, 25, 23
- (d)9, 12, 26, 23
Answer
Why
Correct — D.
Rule: reverse value = 27 − alphabet position, since Z = 27 − 26 = 1 and A = 27 − 1 = 26.
R(18) → 27 − 18 = 9
O(15) → 27 − 15 = 12
A(1) → 27 − 1 = 26
D(4) → 27 − 4 = 23
ROAD = 9, 12, 26, 23 → option (d).
Why the others are wrong
- (a)10, 12, 25, 23 — 10 is the reverse value of Q, not R: 27 − 18 = 9. The option also codes A as 25, which is B's value.
- (b)9, 12, 25, 23 — 25 for A is B's reverse value. R, O and D are right, but A is the 26th letter counting back from Z, so it codes as 26.
- (c)9, 13, 25, 23 — 13 for O is N's reverse value, 27 − 14. O is the 15th letter, so it codes as 27 − 15 = 12, and A should be 26, not 25.
Concept
Reverse coding numbers the alphabet from the far end: Z = 1, Y = 2 … A = 26. A letter's forward and reverse numbers always add to 27, because Z is 26 one way and 1 the other.
So there is no need to count back from Z. Take the forward position you already know and subtract it from 27.
Each wrong option carries at least one value that is one off: 10 for R, 13 for O, 25 for A. Counting back from Z by hand invites that slip, and 27 − position avoids it.
Key facts
- Forward position + reverse position = 27 for every letter.
- R is 18th forwards and 9th in reverse.
- M and N sit in the middle: M is 13 forwards and 14 in reverse.
- E = 5, J = 10, O = 15, T = 20, Y = 25 are quick anchors for forward positions.
Study next
Common traps
- Coding A as 25, as options (a), (b) and (c) all do. Counting back from Z, A is the 26th letter, so it codes as 26.
- Counting back from Z by hand and landing one letter off
17 Sep 2024, 12:30, Reasoning Q.21 uses the same 27 rule as an analogy: ACKO : ZXPL swaps each letter for its opposite, and PUKE is keyed KFPV.
14 Sep 2025, 09:00, Reasoning Q.12 does the same with DINS : WRMH, and EKPT is keyed VPKG.
Related PYQs
No directly related past PYQ was found.