If + = ×, − = ^, × = −, evaluate: 5 − 2 × 3 + 1
- (a)22
- (b)23
- (c)24
- (d)25
Answer
Why
Correct — A.
Rule: substitute all three signs, then powers before × and −.
Printed: 5 − 2 × 3 + 1
Substituted: 5 ^ 2 − 3 × 1
Power: 5 ^ 2 = 5² = 25
Multiplication: 3 × 1 = 3
Subtraction: 25 − 3 = 22 → option (a).
Why the others are wrong
- (b)23 — 23 is 25 − 3 + 1, which leaves the printed + as addition. The code turns + into ×, so the tail is 3 × 1 = 3 and the value is 22.
- (c)24 — 24 is 25 − 1. It would need 3 × 1 to be 1, but 3 × 1 = 3, so 25 − 3 = 22.
- (d)25 — 25 is 5² alone, before anything is taken away. The substituted expression still has − 3 × 1 to apply, which brings it to 22.
Concept
This code has three substitutions: + becomes ×, − becomes ^ (raise to a power), and × becomes −. Swap all three before any arithmetic.
Then keep the order of operations: powers first, then × and ÷, then + and −. 5 ^ 2 is worked first, then 3 × 1, and only then the subtraction.
^ is the usual keyboard sign for a power, so 5 ^ 2 means 5 × 5. The key, 22, confirms that reading: 5² − 3 × 1 = 22.
Key facts
- The code: + is ×, − is ^ (power), × is −.
- 5 − 2 × 3 + 1 becomes 5 ^ 2 − 3 × 1.
- Powers come before multiplication, and multiplication before subtraction.
Study next
Common traps
- Replacing − and × but leaving + as addition, which gives 23
- Stopping at 5² = 25 and choosing option (d)
12 Sep 2025, 09:00, Reasoning Q.25 sets the same kind of substitution without a power: # = ×, @ = −, $ = +, so 9 # 2 @ 3 $ 1 becomes 9 × 2 − 3 + 1, keyed 16.
Reasoning Q.18 of this shift also turns on powers: 8 # 2 = 64 and 7 # 3 = 343, where # raises the first number to the power of the second.
Related PYQs
No directly related past PYQ was found.