What is the value of:(√18 + √2)²−(√8 + √2)²
- (a)14
- (b)15
- (c)16
- (d)17
Answer
Why
Correct — A. Write each root as a multiple of √2, then square.
√18 = √(9 × 2) = 3√2, so √18 + √2 = 4√2
√8 = √(4 × 2) = 2√2, so √8 + √2 = 3√2
Square the first: (4√2)² = 16 × 2 = 32
Square the second: (3√2)² = 9 × 2 = 18
Subtract: 32 − 18 = 14 → option (a)
Why the others are wrong
- (b)15 — 15 is odd, but the two squares, 32 and 18, are both even, so their difference must be even. No correct working reaches 15.
- (c)16 — 16 would need (√8 + √2)² to be 16, that is √8 + √2 = 4. But √8 + √2 = 3√2 ≈ 4.24, and its square is 18.
- (d)17 — 17 is odd as well. Check each square by expansion: 18 + 2 + 2√36 = 32 and 8 + 2 + 2√16 = 18, so the gap is 14.
Concept
Simplify the roots before squaring. √18 and √8 both hide a √2: √18 = 3√2 and √8 = 2√2. Once each bracket is a multiple of √2, squaring is just (number)² × 2.
The direct route gives the same numbers. (√a + √b)² = a + b + 2√(ab), so (√18 + √2)² = 20 + 2√36 = 32 and (√8 + √2)² = 10 + 2√16 = 18.
Taking the brackets as a = √18 + √2 and b = √8 + √2, the identity a² − b² = (a − b)(a + b) gives a third route: a − b = √2 and a + b = 7√2, so the value is √2 × 7√2 = 14.
Key facts
- √18 = 3√2 and √8 = 2√2.
- (√a + √b)² = a + b + 2√(ab).
- (k√2)² = 2k², so (4√2)² = 32 and (3√2)² = 18.
Study next
Common traps
- Squaring term by term: (√18 + √2)² is not 18 + 2. The cross term 2√36 = 12 is missing.
- Adding under one root: √18 + √2 is 4√2, not √20.
The same √2 simplification decides 14 Sep 2025, 16:00, Quant Q.23, where √50 + √18 − √8 = 5√2 + 3√2 − 2√2 = 6√2.
At 12 Sep 2025, 12:30, Quant Q.1, (√8 + √2)² = 18 is what shows √8 + √2 is larger than √3 + √5, whose square is 8 + 2√15 ≈ 15.75.
Related PYQs
No directly related past PYQ was found.