If 'READ' is coded as T2@3, and 'DEAR' is coded as 3@2T, then what is the code for 'DARE'?

Correct — A.
Rule: read each letter's symbol from READ = T2@3.

READ → R = T, E = 2, A = @, D = 3

DARE = D A R E
= 3 @ T 2 = 3@T2 → option (a).

Why the others are wrong

• (b)
  T@23 — T@23 starts with T, which is R's symbol. DARE starts with D, and D's symbol is 3 in both example codes.
• (c)
  @32T — @32T starts with @. DARE's first letter is D, and D = 3 in both READ = T2@3 and DEAR = 3@2T.
• (d)
  @32Y — @32Y contains Y, a symbol in neither example code. Every symbol must come from T, 2, @ and 3, and the code must open with D's 3.

A letter-to-symbol code gives each letter one fixed symbol. DARE uses the same four letters as READ, so it needs no new symbol, only a new order.

Write DARE's letters in turn and replace each with its symbol: D, A, R, E becomes 3, @, T, 2.

R and D are coded the same way in both examples (R = T, D = 3), which already fixes the first and third places of DARE's code.

Key facts

• From READ = T2@3: R = T, E = 2, A = @, D = 3.
• R = T and D = 3 hold in both example codes.
• DARE under READ's symbols reads 3@T2.

Common traps

• Matching on symbols alone: options (a), (b) and (c) all use exactly T, 2, @ and 3, so only the order separates them
• Taking E and A from DEAR's code, which gives 32T@, a code none of the options prints

No directly related past PYQ was found.