In a certain code language, each letter is assigned a unique digit. Based on the given codes for specific words, determine the code for the target word using the same logic. If SPEED is coded as 83551 and COOL is coded as 9226, then how will SCOOP be coded

Correct — C.
Rule: each letter keeps one digit in every word.

SPEED = 83551 → S = 8, P = 3, E = 5, D = 1
COOL = 9226 → C = 9, O = 2, L = 6

SCOOP = S C O O P
= 8 9 2 2 3 = 89223 → option (c).

Why the others are wrong

• (a)
  89213 — 89213 gives the second O the digit 1, which is D's code in SPEED. Both O's must read 2, as they do in COOL = 9226.
• (b)
  89276 — 89276 ends in 7 and 6. Six is L's code and 7 is in neither given code; SCOOP's last two letters, O and P, must be 2 and 3.
• (d)
  89327 — 89327 puts 3 in the third place, but 3 is P's code. The third letter is O, which COOL fixes as 2, and 7 is in neither given code.

In a letter-to-digit code every letter has one fixed digit, whatever word it sits in. Build the key from the given words, then read the target off it letter by letter.

The repeated letters confirm the key: SPEED's double E shows as 55 and COOL's double O as 22.

SCOOP takes S and P from SPEED and C and O from COOL, so every digit is already known.

Key facts

• From SPEED = 83551: S = 8, P = 3, E = 5, D = 1.
• From COOL = 9226: C = 9, O = 2, L = 6.
• A repeated letter must show as a repeated digit in the code.

Common traps

• Taking a digit from the right word but the wrong letter
• Missing that both O's of SCOOP take the same digit

No directly related past PYQ was found.