How many hemispheres with a radius of 3 cm can be produced by melting down a hemisphere with a radius of 12 cm?
- (a)32
- (b)64
- (c)12
- (d)54
Answer
Why
Correct — B. Melting keeps the volume, so divide the large volume by one small volume.
Large: (2⁄3)π × 12³ = (2⁄3)π × 1728 = 1152π
Small: (2⁄3)π × 3³ = (2⁄3)π × 27 = 18π
Number = 1152π ÷ 18π = 64 → option (b)
Shortcut: (12 ÷ 3)³ = 4³ = 64.
Why the others are wrong
- (a)32 — 32 is the number of full spheres of radius 3 cm, each (4⁄3)π × 27 = 36π: 1152π ÷ 36π = 32. The pieces here are hemispheres, half that size, so there are twice as many.
- (c)12 — 12 hemispheres of 18π use only 216π of the 1152π. The radius shrinks by a factor of 4, and the volume by 4³ = 64, not by 12.
- (d)54 — 54 hemispheres use 54 × 18π = 972π, leaving 180π of metal, enough for 10 more. The full count is 1152π ÷ 18π = 64.
Concept
Volume scales with the cube of the radius. A hemisphere of radius 12 is a hemisphere of radius 3 enlarged 4 times in every direction, so it holds 4³ = 64 times the metal.
The shortcut needs the same shape on both sides: hemisphere to hemisphere, or sphere to sphere. Mixing shapes needs the full volume formulas.
Key facts
- Volume of a hemisphere = (2⁄3)πr³.
- Solids of the same shape: volume ratio = (ratio of radii)³.
- A sphere of radius r holds the metal of two hemispheres of radius r.
Study next
Common traps
- Using the radius ratio 4, or its square 16, instead of the cube 64.
- Using the full-sphere volume for the small pieces, which halves the count to 32.
18 Sep 2025, 12:30, Quant Q.11 runs the volume balance the other way, adding the cubes of 2 and 4 to recast two hemispheres into one. 15 Sep 2025, 09:00, Quant Q.14 melts a sphere into 8 equal spheres, so each has half the radius.
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