In the following question, a pair of letters is given, followed by its corresponding product of alphabetical positions (A = 1, B = 2, ..., Z = 26). A second pair of letters is given without its product. Identify the correct product for the second pair that maintains the same relationship as the first. B×D : 2×4 :: G×J : ?
- (a)6×11
- (b)7×10
- (c)8×9
- (d)5×12
Answer
Why
Correct — B.
Rule: write each letter as its alphabet position, keeping the × between them.
First pair: B = 2, D = 4 → 2×4.
Second pair: G = 7, J = 10 → 7×10 → option (b).
Why the others are wrong
- (a)6×11 — 6×11 is F×K, one letter outside G and J on each side. G is the 7th letter, not the 6th.
- (c)8×9 — 8×9 is H×I, the two letters between G and J. The positions of G and J themselves are 7 and 10.
- (d)5×12 — 5×12 is E×L, two letters outside G and J on each side. J is the 10th letter, not the 12th.
Concept
The relation is letter → alphabet position, and the answer keeps the first pair's form: two positions joined by ×, not the product worked out.
Anchor positions save counting from A. E = 5, J = 10, O = 15, T = 20, so G is two after E (7) and J is 10 outright.
Every option adds up to 17: 6 + 11, 7 + 10, 8 + 9 and 5 + 12. A check on the sum alone cannot pick the answer, so match the positions one by one.
Key facts
- G is the 7th letter and J the 10th.
- Anchor positions: E = 5, J = 10, O = 15, T = 20, Z = 26.
- All four options sum to 17, so only the separate positions tell them apart.
Study next
Common traps
- Checking only that the two numbers add to 17, which every option does
- Miscounting G as the 6th or 8th letter without an anchor
14 Sep 2025, 09:00, Reasoning Q.13 uses the same stem on D and K, keyed 4×11 (b).
15 Sep 2025, 16:00, Reasoning Q.13 asks it on T and Z, keyed 20×26 (a).
Related PYQs
No directly related past PYQ was found.