Identify the odd number: 1, 8, 27, 64, 121, 216
- (a)64
- (b)121
- (c)216
- (d)27
Answer
Why
Correct — B. Test each number against the cubes 1³, 2³, 3³ and so on.
Rule: the list is n³ for n = 1 to 6.
1 = 1³, 8 = 2³, 27 = 3³, 64 = 4³
Fifth place should be 5³ = 125, but the list has 121 = 11²
216 = 6³
121 is not a cube, so it is the odd number: option (b).
Why the others are wrong
- (a)64 — 64 = 4³, the fourth cube, in fourth place. It is also 8², but being a square as well does not break the cube pattern.
- (c)216 — 216 = 6³, the sixth cube, in sixth place, right after the slot where 125 belongs.
- (d)27 — 27 = 3³, the third cube, in third place. It is odd in the even/odd sense, but so are 1 and 121, so parity decides nothing.
Concept
An odd-number list is one family of numbers with one entry that breaks it. Name the family first: 1, 8, 27 and 64 are the first four cubes, and 216 is 6³.
Here the odd entry is a near miss: 121 sits 4 below 125, the cube that belongs in fifth place, and 121 is a square, 11².
'Odd' here means the entry that breaks the pattern. In the even/odd sense, 1, 27 and 121 are all odd, so that reading cannot pick one answer.
Key facts
- The first six cubes are 1, 8, 27, 64, 125 and 216.
- 121 = 11², a square but not a cube.
- 64 = 8² = 4³, both a square and a cube, like 1.
Study next
Common traps
- Reading 'odd' as not even: 1, 27 and 121 are all odd numbers, so no single answer comes out.
- Letting 121 pass as 125: the two differ by 4, and a quick eye slides past.
A squares series is asked at 14 Sep 2025, 09:00, Reasoning Q.18, where 1, 4, 9, 16, ?, 36 is completed by 25.
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