Choose the odd one:
- (a)2, 4, 8
- (b)3, 9, 27
- (c)5, 25, 125
- (d)4, 16, 36
Answer
Why
Correct — D.
Rule: n, n², n³ (each term is the one before multiplied by the first).
2, 4, 8 = 2, 2², 2³
3, 9, 27 = 3, 3², 3³
5, 25, 125 = 5, 5², 5³
4, 16 fits 4, 4², but 4³ = 64, not 36. This group breaks the rule → option (d).
Why the others are wrong
- (a)2, 4, 8 — 2, 4, 8 is 2, 2², 2³: each term is the one before multiplied by 2. It follows the rule.
- (b)3, 9, 27 — 3, 9, 27 is 3, 3², 3³, multiplying by 3 at each step. It follows the rule.
- (c)5, 25, 125 — 5, 25, 125 is 5, 5², 5³, multiplying by 5 at each step. It follows the rule.
Concept
An odd-one-out among number groups asks for the property that three groups share and one breaks. Test the simplest relation first: how each term follows from the one before.
Here each regular group is a number followed by its square and cube, so the multiplier equals the first term. In 4, 16, 36 the step from 16 to 36 is ×2.25, not ×4.
4, 16, 36 has a pattern of its own: 2², 4², 6², the squares of even numbers. It is still the odd group, because it does not share n, n², n³ with the rest.
Key facts
- Cubes to know: 2³ = 8, 3³ = 27, 4³ = 64, 5³ = 125.
- Squares of even numbers: 2² = 4, 4² = 16, 6² = 36.
- In n, n², n³ the ratio between neighbouring terms is n.
Study next
Common traps
- Seeing 4 and 16 fit 4, 4² and accepting the group without checking the third term
- Spotting 2², 4², 6² in 4, 16, 36 and then hunting for a squares pattern in the other groups
12 Sep 2025, 09:00, Reasoning Q.18 also sets three-number groups as an odd-one-out, but its rule is primality: 4, 6, 8 is keyed as the group with no prime.
Related PYQs
No directly related past PYQ was found.