If 16+11=A and 1⁄9=B, and A % B=(A×B)−1, then what is A % B?

- (a)0
- (b)−3
- (c)2
- (d)5
Answer
Why
Correct — C. Work out A and B, then apply the rule the stem defines.
Rule: A % B = (A × B) − 1.
A = 16 + 11 = 27
B = 1⁄9
A × B = 27 × 1⁄9 = 3
A % B = 3 − 1 = 2, option (c).
Why the others are wrong
- (a)0 — 0 would need A × B = 1, which means A = 9. But 16 + 11 = 27, so A × B = 3.
- (b)−3 — −3 would need A × B = −2. A and B are both positive, so their product is positive, and the result is 3 − 1 = 2.
- (d)5 — 5 would need A × B = 6, which means A = 54, twice the real sum of 27.
Concept
Here % is not a percentage. The stem defines it for this question: A % B = (A × B) − 1. Your job is to substitute, not to guess what the symbol usually means.
Find A and B first, keep B as the fraction 1⁄9, and multiply. 27 is a multiple of 9, so the product is a whole number, 3.
The stem prints B as a stacked fraction, one over nine. Misreading it as 19 or 9 gives 27 × 19 − 1 = 512 or 27 × 9 − 1 = 242, and neither is an option.
Key facts
- A = 16 + 11 = 27 and B = 1⁄9.
- 27 × 1⁄9 = 3, so (A × B) − 1 = 2.
- A symbol defined in the stem overrides its everyday meaning.
Study next
Common traps
- Reading % as a percentage and taking 27 per cent of something.
- Forgetting the final − 1 and looking for 3, which is not offered.
An operation defined inside the stem is also set at 12 Sep 2025, 16:00, Reasoning Q.23, where a % b = a + 2b = 37 gives a = 27 and b = 5.
12 Sep 2025, 12:30, Reasoning Q.20 instead makes you rebuild the rule for $ from two samples.
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