What is the central angle of a sector with an arc length of 10 cm in a circle of radius 5 cm?
- (a)6 radians
- (b)3 radians
- (c)2 radians
- (d)4 radians
Answer
Why
Correct — C. In radians, a central angle is arc length ÷ radius, because arc = radius × angle.
θ = l ÷ r
θ = 10 ÷ 5 = 2
Check: 5 × 2 = 10 cm, the given arc ✓
2 radians → option (c)
Why the others are wrong
- (a)6 radians — 6 radians would need an arc of 5 × 6 = 30 cm. That is nearly the whole circumference, 2π × 5 ≈ 31.4 cm, not a 10 cm arc.
- (b)3 radians — 3 radians would need an arc of 5 × 3 = 15 cm, half as long again as the 10 cm arc given.
- (d)4 radians — 4 radians would need an arc of 5 × 4 = 20 cm, twice the given 10 cm. Arc ÷ radius is 2, not 4.
Concept
A radian is the central angle whose arc equals the radius. An arc of r subtends 1 radian, an arc of 2r subtends 2 radians.
That gives the working rule l = rθ, with θ in radians, so θ = l ÷ r. Both lengths are in cm and cancel, which is why a radian carries no unit.
Here the arc is exactly twice the radius, so the angle is 2 radians, about 114.6°.
l = rθ needs θ in radians. With θ in degrees the arc is (θ ⁄ 360) × 2πr, and 114.6° gives (114.6 ⁄ 360) × 2π × 5 ≈ 10 cm, the same arc.
Key facts
- Arc length l = rθ, with θ in radians.
- 1 radian = 180° ⁄ π ≈ 57.3°, so 2 radians ≈ 114.6°.
- A full turn is 2π ≈ 6.28 radians, so 6 radians is just short of one turn.
- Sector area = ½ r²θ = ½ × l × r.
Study next
Common traps
- Using l = rθ with θ in degrees. The formula needs radians, so convert first or use (θ ⁄ 360) × 2πr.
- Reading 2 radians as 2°. A radian is about 57.3°, so this sector's angle is about 114.6°, an obtuse one.
Arc and radius together also decide 9 Sep 2024, 12:30, Quant Q.19, where the sector area is ½ × l × r = ½ × 11 × 15.75 = 86.625 cm².
Radian-to-degree conversion appears at Quant Q.17 of this paper (5π⁄4 = 225°) and on 14 Sep 2025, 16:00, Quant Q.18 (2.5 radians ≈ 143.24°).
Related PYQs
No directly related past PYQ was found.