Which one among the following is the correct focal length of a combination of lenses of power 2.5 D and -2.0 D?
- (a)+0.5 m
- (b)-0.5 m
- (c)+2.0 m
- (d)-2.0 m
Correct — C, +2.0 m. Lens powers add algebraically: the combined power P = P1 + P2 = 2.5 D + (-2.0 D) = +0.5 D. The focal length is the reciprocal of the power in metres, f = 1/P = 1/0.5 = +2.0 m. The positive sign shows the combination behaves as a converging (convex) lens.
- (a)+0.5 m — This wrongly takes 0.5 as the focal length; 0.5 is the combined power in dioptres, and f = 1/P = 1/0.5 = 2.0 m, not 0.5 m.
- (b)-0.5 m — Doubly wrong — it uses 0.5 as a focal length and makes it negative, whereas the net power is positive (+0.5 D).
- (d)-2.0 m — The magnitude 2.0 m is right, but the sign is wrong: the net power is +0.5 D (converging), so the focal length is +2.0 m, not -2.0 m.
The power of a lens is P = 1/f, measured in dioptres (D) when f is in metres; a converging (convex) lens has positive power and a diverging (concave) lens negative power. For thin lenses placed in contact the powers simply add: P = P1 + P2, and the resultant focal length is f = 1/P.
First add the powers (2.5 + (-2.0) = 0.5 D), then invert to get the focal length (f = 1/0.5 = 2.0 m). Because the result is positive, the pair acts as a converging lens — pointing to +2.0 m.
- Power P = 1/f (f in metres); its unit is the dioptre (D).
- For thin lenses in contact, powers add: P = P1 + P2.
- Here P = 2.5 + (-2.0) = 0.5 D, so f = 1/0.5 = +2.0 m.
- Positive power/focal length means a converging (convex) lens; negative means a diverging (concave) lens.
- Forgetting to invert power to get focal length (0.5 D gives 2.0 m, not 0.5 m).
- Dropping the sign — a net positive power means a positive (converging) focal length.
- Subtracting the powers instead of adding them algebraically.
Exams give two lens powers and ask for the combined power or focal length — add the powers (with sign) and take the reciprocal for f.
No directly related past PYQ was found.
- practice — not a real PYQ
The power of a lens of focal length 50 cm is:
- (a)0.5 D
- (b)2 D
- (c)5 D
- (d)50 D
Answer(b) 2 D — P = 1/f = 1/0.5 m = 2 dioptres.
- practice — not a real PYQ
Two thin lenses of powers +3 D and -1 D are placed in contact. The power of the combination is:
- (a)+2 D
- (b)-2 D
- (c)+4 D
- (d)+3 D
Answer(a) +2 D — powers add: 3 + (-1) = +2 D.