After interchanging + & × and 3 & 9, which of the following equations will hold true?
- (a)(3+5)×9=48
- (b)(9+2)×3=10
- (c)(3+7)×9=60
- (d)(9+1)×3=15
Answer
Why
Correct — A. Rule: make both swaps first, + ↔ × and 3 ↔ 9, then evaluate.
(3 + 5) × 9 = 48 becomes (9 × 5) + 3 = 48
Bracket: 9 × 5 = 45
Then: 45 + 3 = 48, equal to the right side ✓
The equation holds → option (a)
Why the others are wrong
- (b)(9+2)×3=10 — After the swaps it reads (3 × 2) + 9 = 6 + 9 = 15. The right side is 10, so the equation fails.
- (c)(3+7)×9=60 — After the swaps it reads (9 × 7) + 3 = 63 + 3 = 66. The right side is 60, so the equation fails.
- (d)(9+1)×3=15 — After the swaps it reads (3 × 1) + 9 = 3 + 9 = 12. The right side is 15, so the equation fails.
Concept
An interchange item gives swaps to make before any arithmetic. Here every + becomes ×, every × becomes +, every 3 becomes 9 and every 9 becomes 3.
Rewrite the whole equation, keeping the brackets where they are, and only then evaluate. The bracket is worked first, so 9 × 5 comes before the + 3.
None of the right-hand sides here, 48, 10, 60 and 15, is a 3 or a 9, so they stay as printed.
As printed, before the swaps, none of the four equations is true: (3 + 5) × 9 is 72, not 48. The swaps are what make option (a) balance.
Key facts
- After the swaps, option (a) reads (9 × 5) + 3 = 48.
- Options (b), (c) and (d) evaluate to 15, 66 and 12 against printed 10, 60 and 15.
- Brackets are worked first, then × and ÷, then + and −.
Study next
Common traps
- Swapping the signs but not the numbers: (3 × 5) + 9 = 24, not 48.
- Swapping in two passes, 3 → 9 and then every 9 → 3, which turns the new 9s straight back into 3s.
The same double swap is set at 14 Sep 2025, 12:30, Reasoning Q.22, with + ↔ × and 15 ↔ 30, where (15 + 4) × 30 = 135 becomes (30 × 4) + 15 = 135.
Related PYQs
No directly related past PYQ was found.