If a % b = 37, where a % b = a + 2b, what is the value of a and b?
- (a)25,5
- (b)27, 5
- (c)16, 10
- (d)27, 10
Answer
Why
Correct — B. Rule: a % b means a + 2b, so the pair must satisfy a + 2b = 37.
Test a = 27, b = 5:
2b = 2 × 5 = 10
a + 2b = 27 + 10 = 37 ✓
The pair 27, 5 is option (b).
Why the others are wrong
- (a)25,5 — 25 + 2 × 5 = 25 + 10 = 35, which is 2 short of 37. With b = 5, a must be 37 − 10 = 27.
- (c)16, 10 — 16 + 2 × 10 = 16 + 20 = 36, which is 1 short of 37. With b = 10, a would have to be 17.
- (d)27, 10 — 27 + 2 × 10 = 27 + 20 = 47, not 37. With a = 27, 2b must be 10, so b is 5, not 10.
Concept
A defined operator is a formula in disguise. Replace a % b with a + 2b and the question becomes one equation: a + 2b = 37.
One equation in two unknowns cannot be solved outright, so the options do the work: substitute each pair and keep the one that gives 37.
Double b before adding. The 2 belongs to b alone, not to a or to the sum.
The question asks for "the value of a and b", but a + 2b = 37 alone allows many pairs, such as 35 and 1 or 17 and 10. The four options are what make the answer unique.
Key facts
- By the question's definition, a % b = a + 2b.
- 27 + 2 × 5 = 37.
- One linear equation in two unknowns has many solutions, so the options decide.
Study next
Common traps
- Adding b instead of 2b, which makes option (d) look right: 27 + 10 = 37.
- Trying to solve a + 2b = 37 outright instead of testing the four pairs.
12 Sep 2025, 16:00, Reasoning Q.15 sets the same x + 2y shape with a second equation beside it, x − y = 5, and that second equation is what fixes one pair (x = 8, y = 3).
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