If A:B = 6 : 8 and B:C = 5 : 12, then A:B:C is:
- (a)10:23:14
- (b)11:32:44
- (c)14:31:28
- (d)15:20:48
Answer
Why
Correct — D. Make B the same number in both ratios, then read all three terms off together.
A : B = 6 : 8 and B : C = 5 : 12
B is 8 in the first and 5 in the second; LCM(8, 5) = 40
Multiply the first by 5: A : B = 30 : 40
Multiply the second by 8: B : C = 40 : 96
So A : B : C = 30 : 40 : 96
Divide throughout by 2: 15 : 20 : 48 → option (d)
Why the others are wrong
- (a)10:23:14 — In 10 : 23 : 14 the first two terms give A : B = 10 : 23, which is no scaling of 6 : 8, and C comes out smaller than B.
- (b)11:32:44 — 11 : 32 : 44 breaks the second link: B : C = 32 : 44 reduces to 8 : 11, while the question fixes B : C = 5 : 12.
- (c)14:31:28 — In 14 : 31 : 28 the last term is smaller than B, but B : C = 5 : 12 makes C more than twice B.
Concept
Two ratios sharing a term are joined by scaling until that shared term matches. B appears as 8 in A : B and as 5 in B : C, so scale both to the LCM of 8 and 5, which is 40.
Multiplying every term of a ratio by the same non-zero number leaves the ratio unchanged, which is why 30 : 40 : 96 and 15 : 20 : 48 say exactly the same thing.
A faster check on multiple choice: any correct option must have its first two terms in the ratio 3 : 4 and its last two in 5 : 12. Only one option survives both tests.
Key facts
- To combine A : B with B : C, scale each so that B is the LCM of the two B-terms.
- A ratio is unchanged when every term is multiplied or divided by the same non-zero number.
- In the answer 15 : 20 : 48, the first pair reduces to 3 : 4 (= 6 : 8) and the second pair is 20 : 48 = 5 : 12.
Study next
Common traps
- Writing A : B : C = 6 : 8 : 12 by carrying C straight across, ignoring that B is 8 in one ratio and 5 in the other.
- Reducing 6 : 8 to 3 : 4 first and then losing track of the factor needed for C.
- Stopping at 30 : 40 : 96 and not recognising it as the option 15 : 20 : 48.
The options here are in lowest terms, so a candidate who reaches 30 : 40 : 96 has to divide before looking for it. The same shift's Quant Q.9 takes the next step and compares one figure against an average.
Related PYQs
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