Ifsin x + cos x = √2, what is the value of sin x − cos x?
- (a)0
- (b)1
- (c)2
- (d)3
Answer
Why
Correct — A. Square the given sum and use sin²x + cos²x = 1.
Square: (sin x + cos x)² = (√2)² = 2
Expand: 1 + 2 sin x cos x = 2, so 2 sin x cos x = 1
Square the difference: (sin x − cos x)² = 1 − 2 sin x cos x
Substitute: 1 − 1 = 0
So sin x − cos x = 0 → option (a)
Why the others are wrong
- (b)1 — 1 needs (sin x − cos x)² = 1, so 2 sin x cos x = 0. Then (sin x + cos x)² would be 1, not the 2 the stem gives.
- (c)2 — 2 is impossible for any x: sin x − cos x = √2 sin(x − 45°), so it never exceeds √2 ≈ 1.41.
- (d)3 — 3 is above the largest value sin x − cos x can take, which is √2 ≈ 1.41. No angle reaches it, whatever the given sum.
Concept
The sum and the difference of sin x and cos x are tied by one identity:
(sin x + cos x)² + (sin x − cos x)² = 2
Given one, the other follows. Here the sum squared is 2, so the difference squared is 0.
√2 is also the largest value sin x + cos x can take. Between 0° and 360° it is reached only at x = 45°, where sin x = cos x.
Check by substitution: at x = 45°, sin x + cos x = √2⁄2 + √2⁄2 = √2, and sin x − cos x = 0.
Key facts
- (sin x + cos x)² = 1 + 2 sin x cos x.
- (sin x − cos x)² = 1 − 2 sin x cos x.
- sin x + cos x and sin x − cos x both lie between −√2 and √2.
Study next
Common traps
- Squaring sin x + cos x as sin²x + cos²x and losing the cross term 2 sin x cos x
- Missing that √2 is the maximum of sin x + cos x, which fixes x = 45° at once
The same squaring step drives 23 Sep 2024, 12:30, Quant Q.5, which gives sin A − cos A = (√3 − √2)⁄2 and asks for sin A × cos A.
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