If "ROME" is coded as "VSQI", what is the code for "GREECE"?
- (a)KVIIGI
- (b)KVHHFD
- (c)KWHHDF
- (d)KVIHHD
Answer
Why
Correct — A.
Rule: every letter moves +4: R→V, O→S, M→Q, E→I.
G→K, R→V, E→I, E→I, C→G, E→I
GREECE → KVIIGI → option (a).
Check: GREECE has E in places 3, 4 and 6, so its code must repeat one letter in those places. KVIIGI is the one option that does.
Why the others are wrong
- (b)KVHHFD — KVHHFD moves the first two Es and the C by +3 (E→H, C→F), then turns the last E into D. The given pair moves every letter +4, so each E must become I.
- (c)KWHHDF — KWHHDF already fails at letter 2: W is R + 5. ROME's own code shows R → V.
- (d)KVIHHD — KVIHHD codes GRE correctly, then gives the second E an H and the last E a D. One rule for every letter means all three Es become I.
Concept
In a uniform shift code, every letter moves the same number of places along the alphabet. Read the shift off the given pair one letter at a time: R(18) → V(22) is +4, and O → S, M → Q, E → I confirm it.
Then apply that step to each letter of the new word. A letter that repeats in the word must repeat in its code, which gives a fast check before any counting.
No letter of GREECE passes Z here, so there is no wrap-around. With a larger shift you would count past Z back to A: W(23) + 4 = 27 → 27 − 26 = 1 = A.
Key facts
- Anchor positions: E5, J10, O15, T20, Y25.
- A uniform shift keeps repeated letters repeated: all three Es of GREECE code to I.
- Past Z, subtract 26: W(23) + 4 = 27 → A(1).
Study next
Common traps
- Losing count partway through a six-letter word: option (d) codes GRE correctly and then drifts
- Coding the same letter two different ways, when each E of GREECE must become I
26 Sep 2024, 12:30, Reasoning Q.2 uses a +3 shift (FUTURE → IXWXUH), and its target JERSEY also repeats E, coded H both times: MHUVHB.
21 Sep 2025, 16:00, Reasoning Q.20 runs a shift backwards: SNAKE → RMZJD is −1, keyed YDAQZ for ZEBRA.
Related PYQs
No directly related past PYQ was found.