Find the option that best completes the analogy. AG : IO :: CM : ?
- (a)KO
- (b)KU
- (c)KS
- (d)KW
Answer
Why
Correct — B.
Rule: +8 on each letter.
A(1) + 8 = I(9), and G(7) + 8 = O(15).
C(3) + 8 = K(11), and M(13) + 8 = U(21).
Check: A→G is +6 and I→O is +6. C→M is +10, and K→U is +10 too.
So CM : KU → option (b).
Why the others are wrong
- (a)KO — KO gets K right but moves M only +2, to O. The first pair moved both letters by 8, so M must go to U.
- (c)KS — KS moves M by +6, to S. That is the gap inside AG, not the shift between the pairs, which is +8.
- (d)KW — KW moves M by +10, to W. That is the gap inside CM, not the +8 shift that carries A to I and G to O.
Concept
A letter-pair analogy asks how the second cluster is made from the first. Convert to positions and take the difference letter by letter: A to I is +8, and G to O is +8.
All four options start with K (C + 8), so the second letter decides. A useful cross-check: a constant shift keeps the gap inside a pair, so CM's +10 must reappear as the +10 of KU.
Options (c) and (d) match the two gaps that sit inside the pairs, +6 in AG and +10 in CM. The rule is the gap between the pairs, +8.
Key facts
- A(1) to I(9) and G(7) to O(15) are both +8.
- C(3) + 8 = K(11) and M(13) + 8 = U(21).
- A constant shift keeps the gap within a pair: AG and IO are both +6, CM and KU both +10.
Study next
Common traps
- Using the gap inside a pair (+6 or +10) as the shift
- Checking only the first letter, which all four options share
A constant shift on every letter appears at 24 Sep 2024, 09:00, Reasoning Q.7 (LOI : QTN :: VES : AJX, +5, so AND → keyed FSI) and at 18 Sep 2024, 09:00, Reasoning Q.2 (JAP : BSH :: NDZ : FVR, −8, so LCX → keyed DUP).
12 Sep 2025, 09:00, Reasoning Q.14 (TIME : VJOG) shifts its letters by +2, +1, +2, +2, so check every letter rather than assuming one constant.
Related PYQs
No directly related past PYQ was found.