SSC CGL 2024 Tier-I · 9 September 2024, Shift 3 · Quantitative Aptitude · Question 25 of 100

Text as printed on a candidate's response sheet for this shift; answer per SSC's tentative key as marked on that sheet. Solution last reviewed 6 September 2026.

Where this paper and its answers come from

SSC does not publish CGL question papers or a public answer key. The questions and options here are reproduced as printed on a candidate's own response sheet for this shift — the Commission's text, unchanged. Each answer is SSC's tentative key as marked on that sheet; SSC allowed challenges to it and never publishes a final key. The solutions are written by UnlockIAS.

If the length, breadth, and height of a cuboid is 8 cm, 4 cm, and 6 cm, respectively, then the volume (in cm 3 ) of the cuboid is:

(a)192
(b)96
(c)218
(d)172

Answer

Why

Correct — A. The volume of a cuboid is the product of its three perpendicular edges.

V = length × breadth × height
= 8 × 4 × 6
8 × 4 = 32
32 × 6 = 192

V = 192 cm³ → option (a).

The exponent in the question is the instruction: a cubic unit means three lengths multiplied, not two.

Why the others are wrong

(b)
96 — 96 is half of 192 — the product 8 × 4 × 3, with the height read as 3 instead of 6. All three edges enter the product once, at full length.
(c)
218 — 218 is no product of these edges. It sits near the total surface area, 2(8×4 + 4×6 + 6×8) = 208 cm², which is a different quantity in different units.
(d)
172 — 172 is neither the volume, 192, nor the surface area, 208. The product 8 × 4 × 6 is exact, so there is no rounding that could land between them.

Concept

A cuboid is a rectangular box: six rectangular faces and three edge lengths l, b and h meeting at every corner.

Volume = l × b × h, in cubic units, because the base holds l × b unit squares and the box stacks h such layers.

Two other formulas use the same three numbers and are easy to grab by mistake: total surface area = 2(lb + bh + hl), and the space diagonal = √(l² + b² + h²).

The unit is the fastest check — cm³ can only be a volume, cm² only an area.

The stem asks for the volume 'in cm 3', the paper's rendering of cm³. Two of the four options are close to quantities the same edges do produce, so the unit in the stem is worth reading before the arithmetic.

Key facts

Volume of a cuboid = l × b × h, here 8 × 4 × 6 = 192 cm³.
Total surface area = 2(lb + bh + hl), which for these edges is 208 cm².
The space diagonal is √(l² + b² + h²) = √(64 + 16 + 36) = √116 cm.
A volume carries a cubic unit and an area a square one, so the exponent names the formula wanted.

Study next

Total surface area against lateral surface area of a cuboidThe space diagonal √(l² + b² + h²) and where it is askedVolume of a cube as the case l = b = h

Common traps

Computing the surface area 2(lb + bh + hl) = 208 when the volume was asked.
Multiplying only two of the three edges, which produces an area.
Answering in cm² when the stem has fixed the unit as cm³.

SSC uses the cuboid as a one-step recall item and pushes the discrimination into the options — here 218 sits close to the surface area, 208. The harder version supplies the volume and two edges and asks for the third.

Related PYQs

No directly related past PYQ was found.