Simplify: 13 − [7 − (4 + 7) − {7 − (7 − 4 + 7)} + 14]

- (a)9
- (b)13
- (c)26
- (d)0
Answer
Why
Correct — D. Rule: clear brackets from the inside out — round ( ), then curly { }, then square [ ].
(4 + 7) = 11
(7 − 4 + 7) = 10 (left to right, not 7 − 11)
{7 − 10} = −3
[7 − 11 − (−3) + 14] = 7 − 11 + 3 + 14 = 13
13 − 13 = 0 → option (d)
The step that decides the question is − (−3) = + 3: the minus in front of the curly bracket flips the value inside it.
Why the others are wrong
- (a)9 — 9 appears nowhere in the chain. It would need the square bracket to come to 4, and no arrangement of signs on its terms 7, 11, 3 and 14 produces 4.
- (b)13 — 13 is the square bracket's own value, not the expression's. The final step 13 − [ ] is still owed — getting the bracket right and stopping there is the commonest way to drop this mark.
- (c)26 — 26 is 13 + 13 — the bracket added instead of subtracted. The sign standing in front of [ ] is a minus, so the two 13s cancel to zero.
Concept
BODMAS fixes the order, and within brackets the innermost pair goes first: round, then curly, then square.
A minus sign standing in front of a bracket multiplies everything inside it by −1. That is where nearly all the marks in this item are won or lost.
Addition and subtraction of equal rank run left to right, so 7 − 4 + 7 is (7 − 4) + 7 = 10, not 7 − (4 + 7) = −4. The paper puts exactly that string inside the innermost bracket.
The stem is an image. It reads: "Simplify: 13 − [7 − (4 + 7) − {7 − (7 − 4 + 7)} + 14]".
The four options are plain text — 9, 13, 26 and 0.
Key facts
- Innermost brackets are cleared first: round ( ), then curly { }, then square [ ].
- A minus in front of a bracket changes the sign of every term inside it.
- Addition and subtraction of equal precedence work left to right, so 7 − 4 + 7 = 10.
- Here the square bracket comes to 13, and 13 − 13 = 0.
Study next
Common traps
- Reading 7 − 4 + 7 as 7 − (4 + 7) and getting −4 where the answer needs 10.
- Leaving − {7 − 10} as −3 instead of flipping it to +3.
- Marking the bracket's value of 13 rather than the expression's value.
SSC builds this item so that an intermediate value — here the bracket's 13 — is itself an option. Read what the question asked for before marking the number you have just computed.
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