Select the option that is related to the fifth term in the same way as the second term is related to the first term and the fourth term is related to the third term. EYES : FTFZ :: MIND : OENJ :: REST : ?

Correct — D. Rule: swap the two halves of the cluster, then move every letter one place forward.

EYES: halves EY and ES swap to ES EY, then +1 on each letter gives FT FZ = FTFZ.
MIND: halves MI and ND swap to ND MI, then +1 gives OE NJ = OENJ.

REST: halves RE and ST swap to ST RE, then +1 gives TU SF.

That is TUSF -> option (d).

Why the others are wrong

• (a)
  STRE — STRE swaps the halves and stops there. Every letter still has to move one place forward.
• (b)
  STSF — STSF shifts the trailing half only: RE becomes SF, but ST is left standing instead of becoming TU.
• (c)
  TUFS — TUFS gets the leading half right and then writes the trailing half backwards. R and E must come out in that order, as SF.

A five-term analogy hands you two complete worked examples, and the safe method is to build a rule on the first and only trust it once the second confirms it.

Reordering and shifting are separate operations here and they compose in a fixed order: the halves change places, then every letter advances by one.

Because every letter moves the same distance, the fastest check is to add one to each letter of REST, giving SFTU, then look for the option that is SFTU with its halves exchanged.

Key facts

• EYES to FTFZ is the two halves exchanged, then plus one on every letter.
• MIND to OENJ works identically: ND MI becomes OE NJ.
• REST with plus one on every letter is SFTU, and exchanging the halves gives TUSF.

Common traps

• Applying the plus-one and forgetting the half-swap, or the reverse
• Swapping the halves but reversing the letters inside a half
• Fixing the rule on the first pair and never testing it on MIND

No directly related past PYQ was found.